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3 years ago

Answer to the question

Mathematics

1 answer:

dangina [55]3 years ago

7 0

Actually , the picture is not complete, will you please upload it again

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Find the exact circumference of a circle with a diameter of 5 inches

olchik [2.2K]

The answer is 7.85
First, you divide the diameter by two to get the radius (2.5) and then you multiply by pi(3.14) to get 7.85

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3 years ago

If f(x) = 2x ^ 2 + 5 squreroot(x - 2) complete the following statement

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Answer:

hello :

Step-by-step explanation:

f(x) = 2x²+5√(x-2)

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2 years ago

How to find the slope of two points

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-- Find how much 'y' changes from the first point to the second one.

-- Find how much 'x' changes from the first point to the second one.

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3 years ago

Although cities encourage carpooling to reduce traffic congestion, most vehicles carry only one person. For example, 64% of vehi

ira [324]

Answer:

a) 0.7291 is the probability that more than half out of 10 vehicles carry just 1 person.

b) 0.996 is the probability that more than half of the vehicles carry just one person.

Step-by-step explanation:

We are given the following information:

A) Binomial distribution

We treat vehicle on road with one passenger as a success.

P(success) = 64% = 0.64

Then the number of vehicles follows a binomial distribution, where

$P(X=x) = \binom{n}{x}.p^x.(1-p)^{n-x}$

where n is the total number of observations, x is the number of success, p is the probability of success.

Now, we are given n = 10

We have to evaluate:

$P(x \geq 6) = P(x =6) +...+ P(x = 10) \\= \binom{10}{6}(0.64)^6(1-0.64)^4 +...+ \binom{10}{10}(0.64)^{10}(1-0.79)^0\\=0.7291$

0.7291 is the probability that more than half out of 10 vehicles carry just 1 person.

B) By normal approximation

Sample size, n = 92

p = 0.64

$\mu = np = 92(0.64) = 58.88$

$\sigma = \sqrt{np(1-p)} = \sqrt{92(0.64)(1-0.64)} = 4.60$

We have to evaluate the probability that more than 47 cars carry just one person.

$P(x \geq 47)$

After continuity correction, we will evaluate

$P( x \geq 46.5) = P( z > \displaystyle\frac{46.5 - 58.88}{4.60}) = P(z > -2.6913)$

$= 1 - P(z \leq -2.6913)$

Calculation the value from standard normal z table, we have,

$P(x > 46.5) = 1 - 0.004 = 0.996 = 99.6\%$

0.996 is the probability that more than half out of 92 vehicles carry just one person.

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3 years ago

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myrzilka [38]

I think the answer is 3 :))

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3 years ago