A kite would be the right answer
The question is incomplete. Below you will find the missing graph.
The lowest value of the range of the function shown on graph is (B) -2.
Graph is the pictorial representation of the function or mathematical relation.
The lowest value of the graph is the value of y when 
gives the least value.
From the given graph we can clearly see that at 
the graph of the given function approaches the least value which is -2.
So the lowest value of the range of the function shown on the graph is -2.
Hence the correct option is (B).
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<h2>
Hello!</h2>
The answers are:
The possible values for x in the equation, are:
First option, ![5\sqrt[3]{3}](https://tex.z-dn.net/?f=5%5Csqrt%5B3%5D%7B3%7D)
Second option, ![\sqrt[3]{375}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B375%7D)
<h2>
Why?</h2>
To solve the problem, we need to remember the following properties of the exponents and roots:
![a\sqrt[n]{b}=\sqrt[n]{a^{n}*b} \\\\\sqrt[n]{a^{m} }=a^{\frac{m}{n}}\\\\(a^{b})^{c}=a^{b*c}](https://tex.z-dn.net/?f=a%5Csqrt%5Bn%5D%7Bb%7D%3D%5Csqrt%5Bn%5D%7Ba%5E%7Bn%7D%2Ab%7D%20%5C%5C%5C%5C%5Csqrt%5Bn%5D%7Ba%5E%7Bm%7D%20%7D%3Da%5E%7B%5Cfrac%7Bm%7D%7Bn%7D%7D%5C%5C%5C%5C%28a%5E%7Bb%7D%29%5E%7Bc%7D%3Da%5E%7Bb%2Ac%7D)
Then, we are given the expression:
So, finding "x", we have:
![x^{3}=375\\\\(x^{3})^{\frac{1}{3} } =(375)^{\frac{1}{3}}\\\\x=\sqrt[3]{375}=\sqrt[3]{125*3}=\sqrt[3]{125}*\sqrt[3]{3}=5\sqrt[3]{3}](https://tex.z-dn.net/?f=x%5E%7B3%7D%3D375%5C%5C%5C%5C%28x%5E%7B3%7D%29%5E%7B%5Cfrac%7B1%7D%7B3%7D%20%7D%20%3D%28375%29%5E%7B%5Cfrac%7B1%7D%7B3%7D%7D%5C%5C%5C%5Cx%3D%5Csqrt%5B3%5D%7B375%7D%3D%5Csqrt%5B3%5D%7B125%2A3%7D%3D%5Csqrt%5B3%5D%7B125%7D%2A%5Csqrt%5B3%5D%7B3%7D%3D5%5Csqrt%5B3%5D%7B3%7D)
Hence, the possible values for x in the equation, are:
First option,
Second option,
Have a nice day!
Answer:
C. No. The sum of the dimensions of the eigenspaces equals nothing and the matrix has 3 columns. The sum of the dimensions of the eigenspace and the number of columns must be equal.
Step-by-step explanation:
Here the sum of dimensions of eigenspace is not equal to the number of columns, so therefore A is not diagonalizable.
Each transaction has been an analyzed in the trial balance below by showing its effects on the accounting equation-specifically, identifying the accounts and amounts.
<h3>
How to prepare a Trial Balance?</h3>
The Journal Entries are:
Cash 6500
Photography equipment 33500
Capital 40000
Prepaid Insurance 2100
Cash 2100
Office Supplies 880
Cash 880
Cash 3331
Revenue 3331
Utilities Expense 675
Cash 675
Cash account = 6500 - 2100 - 880 + 3331 - 675
Cash Account = 6176
Trial Balance
Debit Credit
Cash 6176
Prepaid Insurance 2100
Supplies 880
Revenue 3331
Utilities Expense 675
Capital 40000
Photography Equipment 33500
Total 43331 43331
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