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forsale [732]
3 years ago
6

Simplify. Assume that no denominator is equal to zero. (2a/a^2) ^-3

Mathematics
1 answer:
Gnesinka [82]3 years ago
5 0

Answer:

I'm pretty sure its either A or C

Step-by-step explanation:

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Johnny rocket is on a cliff and is all set to launch his rocket . He wanted to track its flight on the computer. The equation to
BlackZzzverrR [31]
5000 I think it is that
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2 years ago
An object is launched from a platform. Its height (in meters), xx seconds after the launch, is modeled by: h(x)=-5(x-4)^2+180 Ho
kozerog [31]

Answer:

x=10

Step-by-step explanation:

h(x)=-5(x-4)^2+180

Set y = 0 to find when it hits the ground

0 = -5(x-4)^2+180

Subtract 180 from each side

-180 =-5(x-4)^2+180-180

-180 =-5(x-4)^2

Divide by -5

-180/-5 =-5/-5(x-4)^2

36 = (x-4)^2

Take the square root of each side

±sqrt(36) = sqrt( (x-4)^2)

±6 =  (x-4)

Add 4  to each side

4±6 =  (x-4)+4

4±6=x

x = 10 or -2

But time cannot be negative so x=10

4 0
3 years ago
Read 2 more answers
4 tenths = 3 tenths + what hundredths
GREYUIT [131]

Answer:

0.10 or 0.1 hundredths

4 0
2 years ago
The coroner arrives at the scene of a murder at 11 p.m. She takes the temperature of the body and finds it to be 81.7°F. She wai
solniwko [45]

Answer:

11:45 AM

Step-by-step explanation:

We have that in one hour the body temperature decreased

went down in

81.7 - 80.2 = 1.2

i.e. 1.2 degrees.

Normal body temperature is 98.6 degrees.

The difference between normal and 11 pm is 98.6-81.7 = 16.9

i.e. 16.9 degrees

now to know how much it decreases every hour:

16.9/ 1.5 = 11.26, that is 11 hours and 15 minutes (1/4 of an hour)

If that was 11:00 PM - 11:15 minutes, the murder was at 11:45 AM

7 0
3 years ago
1,000, 2% , 9 months find the simple interest
Anastasy [175]

Answer:

I = 15

Step-by-step explanation:

The formula for finding interest is I=PRT.

I = Interest

P = Principal (dollars)

R = Rate (percent in decimal form)

T = time (in years)

So, I = 1000×0.02×0.75

Multiply those numbers, and get 15 as interest.

4 0
3 years ago
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