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otez555 [7]
3 years ago
10

A bag contains blue and yellow marbles. Two marbles are drawn without replacement. The probability of selecting a blue marble an

d then a yellow marble is 0.37, and the probability of selecting a blue marble on the first draw is 0.55.
What is the probability of selecting a yellow marble on the second draw, if the first marble drawn was blue?
A) 18%
B) 20%
C) 46%
D) 67%
Mathematics
1 answer:
maxonik [38]3 years ago
4 0
Let the probability of selecting a yellow marble on the second draw be x, then
0.55x = 0.37
x = 0.37/0.55 = 0.67 = 67%
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From the given information:

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We are being told that the longest side is the triangle is equal to 40.

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\mathbf{x = 40 \times \dfrac{17}{8}}

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Now for the other two sides 2 and 7, their length is as follows.

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Therefore, we can conclude that the length of the other two sides is 10 and 35 respectively.

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brainly.com/question/2328454

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