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OLga [1]
3 years ago
13

Four times the some of a number plus 2. Eight times a number minus 20

Mathematics
1 answer:
8_murik_8 [283]3 years ago
8 0
4 x N + 2

8 x N -20
n= number hope this helps
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1000 grams decreased by 94
muminat
906 grams.
1000-94=906 grams
4 0
3 years ago
What is the equation of the line x–3y=18 in slope-intercept form?
Minchanka [31]

Answer:

Simple...

you have: x-3y=18

You want to convert it into slope-intercept form or y=mx+b form-->>>

x-3y=18

Isolate the variable-->>

x-3y=18

-x      -x

-3y=-x+18

Now simply divide...

-3y/-3  = -x+18/-3

y=1/3x=6

Thus, your answer.

3 0
3 years ago
Read 2 more answers
What is the sum of the first 37 terms of the arithmetic sequence?
lidiya [134]

Answer:

The sum of the first 37 terms of the arithmetic sequence is 2997.

Step-by-step explanation:

Arithmetic sequence concepts:

The general rule of an arithmetic sequence is the following:

a_{n+1} = a_{n} + d

In which d is the common diference between each term.

We can expand the general equation to find the nth term from the first, by the following equation:

a_{n} = a_{1} + (n-1)*d

The sum of the first n terms of an arithmetic sequence is given by:

S_{n} = \frac{n(a_{1} + a_{n})}{2}

In this question:

a_{1} = -27, d = -21 - (-27) = -15 - (-21) = ... = 6

We want the sum of the first 37 terms, so we have to find a_{37}

a_{n} = a_{1} + (n-1)*d

a_{37} = a_{1} + (36)*d

a_{37} = -27 + 36*6

a_{37} = 189

Then

S_{37} = \frac{37(-27 + 189)}{2} = 2997

The sum of the first 37 terms of the arithmetic sequence is 2997.

6 0
3 years ago
Please help me with this one and explain to me how you found the answer
Aneli [31]

Answer:

i believe its a square :)

Step-by-step explanation:

5 0
3 years ago
How to solve derivative of (sin3x)/x using first principle ​
Leona [35]

\dfrac{d}{dx}(\dfrac{\sin(3x)}{x})

First we must apply the Quotient rule that states,

(\dfrac{f}{g})'=\dfrac{f'g-g'f}{g^2}

This means that our derivative becomes,

\dfrac{\dfrac{d}{dx}(\sin(3x))x-\dfrac{d}{dx}(x)\sin(3x)}{x^2}

Now we need to calculate \dfrac{d}{dx}(\sin(3x)) and \dfrac{d}{dx}(x)

\dfrac{d}{dx}(\sin(3x))=\cos(3x)\cdot3

\dfrac{d}{dx}(x)=1

From here the new equation looks like,

\dfrac{3x\cos(3x)-\sin(3x)}{x^2}

And that is the final result.

Hope this helps.

r3t40

7 0
3 years ago
Read 2 more answers
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