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grigory [225]
3 years ago
13

I have 6 vertices and 9 edges how many faces?

Mathematics
2 answers:
wariber [46]3 years ago
7 0
Its a polyhedron its has 25 faces
den301095 [7]3 years ago
4 0
A polyhedron which has 5 faces. 

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F(x) = 2x3 _ 6x² +13x+5
Jlenok [28]

dont know the answer at all

Step-by-step explanation:

3 0
3 years ago
Suppose a hot air balloon begins descending at a rate of 30ft/min from an elevation of 1250ft. Write an equation to model the ho
galina1969 [7]
Base elevation is 1250 ft
rate is 30 per minute 30m
so, h = 1250 - 30m
as an inclusion, 30 ft per minute is also like 0.5 per second like 1250 - 0.5s
1250/30 means it would be about 42 minutes once it touches the ground.

7 0
3 years ago
The eleventh term from the end of the AP 14, 19, 24, …………., 264 is
vazorg [7]

Answer:

<h2>The eleventh term of the sequence is 64</h2>

Step-by-step explanation:

The sequence given is an arithmetic sequence

14, 19, 24, …………., 264

The nth term of an arithmetic sequence is given as;

Tn = a+(n-1)d where;

a is the first term = 14

d is the common difference = 19-14=24-19 = 5

n is the number of terms = 11(since we are to look for the eleventh term of the sequence)

substituting the given values in the formula given;

T11 = 14+(11-1)*5

T11 = 14+10(5)

T11 = 14+50

T11 = 64

The eleventh term of the sequence is 64

6 0
3 years ago
Ann's first option is a plot of land adjacent to a current park.
oksian1 [2.3K]

Given:

The equation for the area of the first option is:

x^2+200x=166400

Where x is the side length of the current square park.

To find:

The side length of the current square park.

Solution:

We have,

x^2+200x=166400

It can be written as:

x^2+200x-166400=0

Splitting the middle term, we get

x^2+520x-320x-166400=0

x(x+520)-320(x+520)=0

(x-320)(x+520)=0

x=320,-520

We know that the side length of a park cannot be negative. So, the only possible value of x is 320.

Therefore, the most direct method to solve the given equation is splitting the middle term and the side length of the current square park is 320 meters.

4 0
2 years ago
In a large statistics course, 74% of the students passed the first exam, 72% of the students pass the second exam, and 58% of th
11111nata11111 [884]

Answer:

Required probability is 0.784 .

Step-by-step explanation:

We are given that in a large statistics course, 74% of the students passed the first exam, 72% of the students pass the second exam, and 58% of the students passed both exams.

Let Probability that the students passed the first exam = P(F) = 0.74

     Probability that the students passed the second exam = P(S) = 0.72

     Probability that the students passed both exams = P(F \bigcap S) = 0.58

Now, if the student passed the first exam, probability that he passed the second exam is given by the conditional probability of P(S/F) ;

As we know that conditional probability, P(A/B) = \frac{P(A\bigcap B)}{P(B) }

Similarly, P(S/F) = \frac{P(S\bigcap F)}{P(F) } = \frac{P(F\bigcap S)}{P(F) }  {As P(F \bigcap S) is same as P(S \bigcap F) }

                          = \frac{0.58}{0.74} = 0.784

Therefore, probability that he passed the second exam is 0.784 .

5 0
3 years ago
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