You just need to make a line with the most dots that you can. Make the most dots you can fit on one line from the 0 to the end of the graph diagonally and fit as many points as you can. <span />
Answer:
<h3>
9, 10 and 11</h3>
Step-by-step explanation:
x - the smallest of three consecutive integers (the first)
x+1 - the next of three consecutive integers (the second)
x+2 - the last of three consecutive integers (the third)
3(x+2) - three times the third integer
<u>3(x+2)+x </u> - three times the third increased by the first
5(x+1) - five times the second tnteger
<u>5(x+1)-8 </u> - 8 less than five times the second
3(x + 2) + x = 5(x + 1) - 8
3x + 6 + x = 5x + 5 - 8
4x + 6 = 5x - 3
-4x -4x
6 = x - 3
x = 9
x+1 = 10
x+2 = 11
Check: 3×11+9 = 33+9 = <u>42</u>, 5×10-8=50-8 = <u>42</u>
Answer:
Quadrant IV
Step-by-step explanation:
(+, +) -> Quadrant I
(-, +) -> Quadrant II
(-, -) -> Quadrant III
(+, -) -> Quadrant IV
Answer:
4.8%
Step-by-step explanation:
28+12=40
40÷100=0.4
1% - 0.4 teachers
0.4×12=4.8
Answer:
388
Step-by-step explanation:
4+6x64
multiply 6 and 64
6 times 64 = 384
Add 4 to 384
384+4=388
