Answer:
The radius of circle is 3
Step-by-step explanation:
Given the endpoints of diameter of a circle are (6,2) and (0,2)
We know that the equation of circle is
+
= ![r^{2}](https://tex.z-dn.net/?f=r%5E%7B2%7D)
where (x,y) is any point on the circle, (h,k) is center of the circle and r is radius of circle.
To find (h,k): the center is midpoint of diameter
Midpoint of diameter with end points (x1,y1) and (x2,y2) is given by
(
,
)
(
,
)
(3, 2)
Hence (h,k) is (3,2)
Substituting values of (h.k) and (x.y) as (3,2) and (0,2) respectively, we get
+
= ![r^{2}](https://tex.z-dn.net/?f=r%5E%7B2%7D)
= ![3^{2}](https://tex.z-dn.net/?f=3%5E%7B2%7D)
r =3
Hence the radius of the circle is 3