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2 years ago

-8=2y-3x 4y-12+x=0.

Mathematics

2 answers:

andreyandreev [35.5K]2 years ago

7 0

Answer:

x=4 and y=2

Step-by-step explanation:

kobusy [5.1K]2 years ago

7 0

2y-3x=-8
x=-4y+12
<=>
2y-3(-4y+12)=-8
x=-4y+12
<=>
2y+12y-36+8=0
x=-4y+12
<=>
14y-28=0
x=12-4y
<=>
y=2
x=12-4x2
<=>
x=4
y=2

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$\overline{\qquad\qquad\qquad\qquad\qquad\qquad\qquad\qquad\qquad\qquad\qquad\qquad\qquad}$

$\Large\texttt{Process}$

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2. When i=2, $Z_2=1.25,\ X_2=87,$ then

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Now solve the system of equations:

$\left\{\begin{array}{l}-0.25=\dfrac{57-\mu}{\sigma}\\ \\1.25=\dfrac{87-\mu}{\sigma}.\end{array}\right.$

$\left\{\begin{array}{l}-0.25\sigma=57-\mu\\ \\1.25\sigma=87-\mu.\end{array}\right.$

Subtract first equation from the second:

$1.25\sigma-(-0.25\sigma)=87-57,\\ \\1.5\sigma=30,\\ \\\sigma=20.$

Then

$1.25=\dfrac{87-\mu}{20},\\ \\87-\mu=25,\\ \\\mu=87-25=62.$

Answer: the mean is 62, the standard deviation is 20.

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