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3 years ago

PLEASE HELP ASAP!!!

Computers and Technology

1 answer:

Studentka2010 [4]3 years ago

3 0

If you are using CSS :

table {

border-collapse: collapse;

border: 5px solid black;

width: 100%;

}

td {

width: 50%;

height: 2em;

border: 1px solid #ccc;

}

HTML

<table>

<tbody>

</tbody>

</table>

for HTML:

<!DOCTYPE html>

<html>

<head>

<title>Sample table</title>

<style>

table {

border-collapse: collapse;

border: 5px solid black;

width: 100%;

}

td {

width: 50%;

height: 2em;

border: 1px solid #ccc;

}

</style>

</head>

<body>

<table>

<tbody>

</tbody>

</table>

</body>

</html>

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Consider a single-platter disk with the following parameters: rotation speed: 7200 rpm; number of tracks on one side ofplatter:

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Answer:

Given Data:

Rotation Speed = 7200 rpm

No. of tracks on one side of platter = 30000

No. of sectors per track = 600

Seek time for every 100 track traversed = 1 ms

To find:

Average Seek Time.

Average Rotational Latency.

Transfer time for a sector.

Total Average time to satisfy a request.

Explanation:

a) As given, the disk head starts at track 0. At this point the seek time is 0.

Seek time is time to traverse from 0 to 29999 tracks (it makes 30000)

Average Seek Time is the time taken by the head to move from one track to another/2

29999 / 2 = 14999.5 ms

As the seek time is one ms for every hundred tracks traversed. So the seek time for 29,999 tracks traversed is

14999.5 / 100 = 149.995 ms

b) The rotations per minute are 7200

1 min = 60 sec

7200 / 60 = 120 rotations / sec

Rotational delay is the inverses of this. So

1 / 120 = 0.00833 sec

= 0.00833 * 100

= 0.833 ms

So there is 1 rotation is at every 0.833 ms

Average Rotational latency is one half the amount of time taken by disk to make one revolution or complete 1 rotation.

So average rotational latency is: 1 / 2r

8.333 / 2 = 4.165 ms

c) No. of sectors per track = 600

Time for one disk rotation = 0.833 ms

So transfer time for a sector is: one disk revolution time / number of sectors

8.333 / 600 = 0.01388 ms = 13.88 μs

d) Total average time to satisfy a request is calculated as :

Average seek time + Average rotational latency + Transfer time for a sector

= 149.99 ms + 4.165 ms + 0.01388 ms

= 154.168 ms

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3 years ago