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3 years ago

Anyone help me with this please

Mathematics

2 answers:

faust18 [17]3 years ago

6 0

B.
Just trust me on that

Umnica [9.8K]3 years ago

5 0

Option A is the right answer.

We know that the y-intercept is (0, 3), since that's the point on y-axis. Now that we know this, we know the value of 'b'

y = mx + b
y = mx + 3

Now all we have to do is solve for m. Recall that 'm' represents the slope, and that the equation to find the slope is rise/run. Essentially, you have to find two points and figure out the number of units you have to travel through the x-axis and y-axis.

In this question, they've already gave us two points (The black dots) that we can use to find the slope. In order to get the dot on the to the dot on the bottom, we have to go down 5 times. This means that the rise is -5.

Now all we have to do is go right until we reach the point. In this question, you have to go the right 4 times, making the run 4.

And so we've found the slope: -5/4.
Since the slope is 'm,' we can now complete our equation.
y = mx + 3
y = -5/4x + 3

Let me know if you need me to explain anything in more depth :))
-T.B.

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erma4kov [3.2K]

Answer:

a) $97.1\%$ b) $13.6\%$ $c) 772 \:calories$

Step-by-step explanation:

$\mu=1071,\:\sigma=301$

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As you can see in the graph.

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By the rule

We have the interval 68% is equal to the mean plus 1 standard deviation and minus one standard deviation.

$68\%=(\mu-2\sigma,\mu+2\sigma)=(1071-2(301), 1071+2(301)=(469,1672)$

But the question wants to know more than 469 calories, then $13.6\%+34\%+34\%+13.6\%+2.1\%=97.1\%\\$

b. What is the approximate percentage of Chipotle meals with calorie amounts between 1372 calories and 1673 calories?

Check the graph below

This percentage is the interval, which is a quarter of that 95%

$(\mu +\sigma,\mu+2\sigma)=(1372,1673)=\frac{95\%}{4}=13.6\%$

c.. If a particular meal's calorie amount is equal to the 16th percentile of Chipotle meal calorie amounts, how many calories are in the meal?

Since we're dealing with a Normal Curve, then to find the 16th percentile we need:

The Mean and Standard deviation
The Z score and then multiply by that Standard Deviation
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. $Z\: score=-0.994\\\\(-0.994)*301=-299.194\\-299.194+\mu \Rightarrow -299.194+1071=771.806\approx772$

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