The change is the remaining money that is needed to take from the seller so a change of Umberto will be $6.62.
<h3>What is subtraction?</h3>
To subtract in mathematics is to take something away from a group or a number of objects.
The group's total number of items decreases or becomes lower when we subtract from it.
Given that,
Umberto buys a game for $7.89 and some batteries for $5.49.
Total money of buying = 7.89 + 5.49 = $13.38
Now he gives a $20 bill.
Remaining (change) = 20 - 13.38
⇒ $6.62
Hence "The change of Umberto will be $6.62".
For more about subtraction,
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Answer:
Example:
A bag contains 3 black balls and 5 white balls. Paul picks a ball at random from the bag and replaces it back in the bag. He mixes the balls in the bag and then picks another ball at random from the bag.
a) Construct a probability tree of the problem.
b) Calculate the probability that Paul picks:
i) two black balls
ii) a black ball in his second draw
Solution:
tree diagram
a) Check that the probabilities in the last column add up to 1.
b) i) To find the probability of getting two black balls, first locate the B branch and then follow the second B branch. Since these are independent events we can multiply the probability of each branch.
ii) There are two outcomes where the second ball can be black.
Either (B, B) or (W, B)
From the probability tree diagram, we get:
P(second ball black)
= P(B, B) or P(W, B)
= P(B, B) + P(W, B)
98%
Hope this helps you :)
Answer:
Probability of chossing a face card and the month of june = 0.019
Step-by-step explanation:
Let A be the event that a face card is chosen from a deck of 52 cards
And
B be the event that a month is being chosen from 12 months of an year
So,
n(S)for A=52
n(S)for B=12
As a deck of card has total of 12 face cards so
P(A)=12/52
=3/13
P(B)=1/12
As both the events are independent, the probability of A and B is the product of both events’ probabilities.
P(A and B)= P(A)*P(B)
=3/13*1/12
=3/156
=0.019
=(9(1/3))^2+2+4/7
=(3^2)+2+4/7
=(9)+2+4/7
=11+4/7
=81/7
