Find the midpoint of the line segment with the given endpoints. (-3.1, -2.8) and (-4.92, -3.3)
1 answer:
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From the right hand side, we will need to find a way to rewriting 3x²y in terms of cube roots.
We know that 27 is 3³, so if we were to rewrite it in terms of cube roots, we will need to multiply everything by itself two more twice. (ie we can rewrite it as ∛(3x²y)³)
Hence, we can say that it's:
![\sqrt[3]{162x^{c}y^{5}} = \sqrt[3]{(3x^{2}y)^{3}} * \sqrt[3]{6y^{d}}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B162x%5E%7Bc%7Dy%5E%7B5%7D%7D%20%3D%20%5Csqrt%5B3%5D%7B%283x%5E%7B2%7Dy%29%5E%7B3%7D%7D%20%2A%20%5Csqrt%5B3%5D%7B6y%5E%7Bd%7D%7D)
![= \sqrt[3]{162x^{6}y^{3+d}}](https://tex.z-dn.net/?f=%3D%20%5Csqrt%5B3%5D%7B162x%5E%7B6%7Dy%5E%7B3%2Bd%7D%7D)
Hence, c = 6 and d = 2
We know that 27 is 3³, so if we were to rewrite it in terms of cube roots, we will need to multiply everything by itself two more twice. (ie we can rewrite it as ∛(3x²y)³)
Hence, we can say that it's:
Hence, c = 6 and d = 2
Answer:
Step-by-step explanation:
I hope I did this right:
So first thing to do is set up the equation.
Next thing to to is subtract 1/3 from both sides to get:
Next up, you will multiply each of the fractions by the opposing value
(multiply 1/8 by 3 and 1/3 by 8)
Alright almost done, by multiplying 24 by 5 you get 120, that will go in the numerator to make the math a lot easier.
K =
Finally, you subtract 123 over 24 by 8 over 24.
K =
Then just simplfy the 115/24 to get