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artcher [175]
3 years ago
12

The number of hours students spent using

Mathematics
1 answer:
djyliett [7]3 years ago
5 0
XY. Electronics can be X and sports Y. Then simply multiply
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PLEASE help! Functions problem!
bezimeni [28]

Answer:

C

Step-by-step explanation:

x = -1 and -7

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3 years ago
REWARDING BRAINLY!!!
riadik2000 [5.3K]

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12

Step-by-step explanation:

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3 years ago
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Eight car dealerships reported the number of cars they sold last month. Car Dealership Number of Cars Sold GMC 84 Chevrolet 81 N
Maksim231197 [3]

Answer:

<h2>10.75</h2>

Step-by-step explanation:

Interquartile R range of an ungrouped data is expressed as R = Q3-Q1 where;

Q3 is the third quartile

Q1 is the first quartile

Given the Car Dealership Number of Cars Sold GMC as 84 Chevrolet 81 Nissan 92 Toyota 92 Ford 95 Honda 94 Hyundai 80 Acura 72

First let us arrange them in ascending order;

72, 80, 81, 84, 92, 92, 94, 95

Q3 = 3(n+1)/4 th observation where n is the total number of cars

Q3 = 3(8+1)/4 = 27/4

Q3 = 6.75th observation

Q3 = 6th obsrvation - 0.75(7th observation - 6th observation)

Q3 = 92-0.75(94-92)

Q3 = 92-0.75(2)

Q3 = 90.5

The 6.75th observation of the data is 90.5

Q1 = (n+1)/4 th observation where n is the total number of cars

Q1 = (8+1)/4 = 9/4

Q1 = 2.25th observation

Q1 = 2nd observation - 0.25(3rd observation - 2nd observation)

Q1 = 80-0.25(81-80)

Q1 = 80-0.25(1)

Q1 = 79.75

Interquartile range = Q3 - Q1

Interquartile range = 90.5 - 79.75

Interquartile range = 10.75

7 0
3 years ago
Is the answer to this a, b, c or d?
sweet-ann [11.9K]
The answer would be D.

To find the hypothenuse, you have to multiply by the square root of 2 and to find the side length is not necessary because it is the same length as the other side length
6 0
3 years ago
Read 2 more answers
An anthropologist wishes to estimate the average height of men for a certain race of people. If the population standard deviatio
mario62 [17]

Answer:

The probability that the difference between the sample mean \bar{x} and the true population mean \mu is : P[|\bar{x}-\mu|\leq0.7]=0.9876

Step-by-step explanation:

Given :

Population standard deviation \sigma=2.8.

Sample size n=100

The sample mean standard deviation=\frac{\sigma}{\sqrt{n}}

To find :

The probability that the difference between the sample mean \bar{x} and the true population mean \mu

\because\frac{\sigma}{\sqrt{n}}=\frac{2.8}{\sqrt{100}}=\frac{2.8}{10}=0.28

Now, the probability that the difference between the sample mean \bar{x} and the true population mean \mu is :

  P[|\bar{x}-\mu|\leq0.7], nis large \Rightarrow \frac{\bar{x}-\mu}{\frac{\sigma}{\sqrt{n}}}=z

\Rightarrow P[\frac{\bar{x}-\mu}{\frac{\sigma}{\sqrt{n}}}

\Rightarrow P[z

\Rightarrow P[-2.5

Therefore, the probability P[|\bar{x}-\mu|\leq0.7]=0.9876

5 0
3 years ago
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