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3 years ago

12

The number of hours students spent using

1 answer:

djyliett [7]3 years ago

5 0

XY. Electronics can be X and sports Y. Then simply multiply

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Line Segment BC has endpoints B (3,5) and C (7,15). Find the missing coordinates of A (x,9) and D (17,y) such that AB and CD are

o-na [289]

Answer:

<em>x=-7</em>

<em>y=11</em>

Step-by-step explanation:

<u>Perpendicular Vectors</u>

Two vectors defined as their endpoints $\vec u=$ and $\vec v=$ are perpendicular if their dot product a.b is zero. The dot product is

$\vec u.\vec v=ac+bd$

In other words

ac+bd=0

Let's treat all the points as the extremes of vectors, so we can easily find the missing coordinates

B (3,5) and C (7,15) define a segment, the vector

$\overrightarrow{BC}==$

The point A is A (x,9), we need to form a vector with B

$\overrightarrow{AB}==$

this vector must be perpendicular to BC, so, applying the dot product we have

$4(x-3)+40=0$

$4x-12=-40$

$x=-7$

The point D is D(17,y), we need to form a vector with C

$\overrightarrow{CD}==$

this vector must be perpendicular to BC, so, applying the dot product we have

$(4)(10)+(10)(y-15)=0$

$40+10y-150=0$

$10y=110$

$y=11$

The points are

$\boxed{A(-7,9), D(17,11)}$

4 0

3 years ago

What is the distance between points A and C?<br> 3.3 units<br> 3.6 units<br> 5.2 units<br> 7.8 units

artcher [175]

Answer:

AC ≈ 7.8 units

Step-by-step explanation:

Calculate the distance d using the distance formula

d = $\sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2 }$

with (x₁, y₁ ) = A (- 4, - 4 ) and (x₂, y₂ ) = C (2, 1 )

AC = $\sqrt{(2-(-4))^2+(1-(-4))^2}$

= $\sqrt{(2+4)^2+(1+4)^2}$

= $\sqrt{6^2+5^2}$

= $\sqrt{36+25}$

= $\sqrt{61}$

≈ 7.8 ( to 1 dec. place )

5 0

2 years ago

Melvin bought a life insurance policy from Martin, and if Melvin dies, the

nalin [4]

Answer:

monica

Step-by-step explanation:

6 0

3 years ago

A student was trying to find the solution to a system of equations, but they were incorrect. Their explanation is shown below.

Lady_Fox [76]

Answer:

no solution

Step-by-step explanation:

if you subtract the equations then you get 0 = 8 and this can never be true; therefore there are no solution

7 0

3 years ago

Find the zeros of each function by using a graph and a table. f(x)=x^2+2x–24.

Alborosie

Explanation

Step 1

$f(x)=x^2+2x-24$

Zeros

A(-6,0) B(4,0)

because

$\begin{gathered} f(x)=x^2+2x-24 \\ f(-6)=(-6)^2+2(-6)-24=36-12-24=0 \\ f(4)=4^2+2\cdot4-24=16+8-24=0 \end{gathered}$

Step 2

table

$\begin{gathered} (-6,0) \\ (4,0) \\ f(-1)=-1^2+2\cdot-1-24=1-2-24=-25 \\ (1,-25) \\ \end{gathered}$

I hope this helps you

5 0

1 year ago