1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
lilavasa [31]
3 years ago
5

Can i get an answer for this​

Mathematics
1 answer:
Dimas [21]3 years ago
8 0

Answer:

Isnt it just 75 degrees?

Step-by-step explanation:

The number in the angle.

You might be interested in
I need helpppp plssss anyone I’m not the best at math :/
Ulleksa [173]

Answer:

C

Step-by-step explanation:

7 0
2 years ago
an inverted conical water tank with a height of 20 ft and a radius of 8 ft is drained through a hole in the vertex (bottom) at a
viktelen [127]

Answer:

the rate of change of the water depth when the water depth is 10 ft is;  \mathbf{\dfrac{dh}{dt}  = \dfrac{-25}{100  \pi} \  \ ft/s}

Step-by-step explanation:

Given that:

the inverted conical water tank with a height of 20 ft and a radius of 8 ft  is drained through a hole in the vertex (bottom) at a rate of 4 ft^3/sec.

We are meant to find the  rate of change of the water depth when the water depth is 10 ft.

The diagrammatic expression below clearly interprets the question.

From the image below, assuming h = the depth of the tank at  a time t and r = radius of the cone shaped at a time t

Then the similar triangles  ΔOCD and ΔOAB is as follows:

\dfrac{h}{r}= \dfrac{20}{8}    ( similar triangle property)

\dfrac{h}{r}= \dfrac{5}{2}

\dfrac{h}{r}= 2.5

h = 2.5r

r = \dfrac{h}{2.5}

The volume of the water in the tank is represented by the equation:

V = \dfrac{1}{3} \pi r^2 h

V = \dfrac{1}{3} \pi (\dfrac{h^2}{6.25}) h

V = \dfrac{1}{18.75} \pi \ h^3

The rate of change of the water depth  is :

\dfrac{dv}{dt}= \dfrac{\pi r^2}{6.25}\  \dfrac{dh}{dt}

Since the water is drained  through a hole in the vertex (bottom) at a rate of 4 ft^3/sec

Then,

\dfrac{dv}{dt}= - 4  \ ft^3/sec

Therefore,

-4 = \dfrac{\pi r^2}{6.25}\  \dfrac{dh}{dt}

the rate of change of the water at depth h = 10 ft is:

-4 = \dfrac{ 100 \ \pi }{6.25}\  \dfrac{dh}{dt}

100 \pi \dfrac{dh}{dt}  = -4 \times 6.25

100  \pi \dfrac{dh}{dt}  = -25

\dfrac{dh}{dt}  = \dfrac{-25}{100  \pi}

Thus, the rate of change of the water depth when the water depth is 10 ft is;  \mathtt{\dfrac{dh}{dt}  = \dfrac{-25}{100  \pi} \  \ ft/s}

4 0
3 years ago
Given f(x) = 6(1-X), what is the value of f(8)?
andrey2020 [161]

Answer:

-42

Step-by-step explanation:

f(8)=6(1-8)

because of that 1-8 is -7 so you times by 6 and get -42

8 0
2 years ago
Jim wants to buy strawberries and raspberries for the company party. Strawberries cost $1.80 per pound and raspberries cost $1.9
Crazy boy [7]

Answer: The answer is A.


Step-by-step explanation: You cant go over the $15 limit and in answer A, the sign shows that 1.80x + 1.95y is less than or equal to 15.


5 0
3 years ago
Read 2 more answers
What is (32x - 7y) - (28x - 11y) *Need the answer AS SOON AS POSSIBLE*
artcher [175]

(32x - 7y) - (28x - 11y)

distribute

32x-7y -28x+11y

4x+4y

3 0
3 years ago
Other questions:
  • Simplify (7+5)^2 divided by 4 x 3 + 9
    6·1 answer
  • MATH HELP!!!!!!!!!!!!!!!!
    11·1 answer
  • Please help i dont get it
    15·2 answers
  • Write this number in standard form four and thirty one hundreths
    8·1 answer
  • WILL GIVE BRAINLIEST IF FAST AND RIGHT
    5·1 answer
  • What is the dollar value of p pennies and d dimes?
    13·1 answer
  • State the domain of <br> f(x) = log2(2x - 5)
    13·1 answer
  • Write equivalent expressions in factored form<br> 2x + 8y
    10·1 answer
  • Find the equation of the line that passes through the point (3,7) and is parallel to the line that passes through (5,5) and (5,3
    7·1 answer
  • Alison has 6 yellow discs, 5 blue discs and 9 red discs which she places in a bag. When she draws one disc out, what is the prob
    13·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!