Answer:
The 90% confidence interval for the mean score of all takers of this test is between 59.92 and 64.08. The lower end is 59.92, and the upper end is 64.08.
Step-by-step explanation:
We have that to find our 
level, that is the subtraction of 1 by the confidence interval divided by 2. So:
Now, we have to find z in the Ztable as such z has a pvalue of 
.
So it is z with a pvalue of 
, so 
Now, find the margin of error M as such
In which 
is the standard deviation of the population and n is the size of the sample.
The lower end of the interval is the sample mean subtracted by M. So it is 62 - 2.08 = 59.92
The upper end of the interval is the sample mean added to M. So it is 62 + 2.08 = 64.08.
The 90% confidence interval for the mean score of all takers of this test is between 59.92 and 64.08. The lower end is 59.92, and the upper end is 64.08.
the first answer is 93000000 and the second answer is 240000
So 6 times 6 is 36 so 36 possibilities and the number that add up to 3 or nine are (2,1; 3,6; 4,5;) so 3 out of 36 or 1 out of 12, the answer is not there
Step-by-step explanation:
are you sure the fuel consumption is given by 6,8 km/l ?
normally it is given by l/100km.
but ok, let's assume this is correct.
it would mean the car can drive 6,8 km with every liter of fuel in the tank.
how many liters will the car need to go 450 km ?
well, as many liters as 6,8 fits into 450 :
450/6,8 = 66.17647059... liters
this is not a very fuel efficient car ...
