-29664 is the correct answer. This mostly deals with the zeros and crossing them off
I think it is 35 but I could be wrong
Answer:
See the explanation
Step-by-step explanation:
We know that
f(x) = 2x⁶ + 3x⁴ - 4x³ + (1/x) - sin2x
Lets calculate the derivatives:
f'(x) = 6(2x⁵) + 4(3x³) - 3(4x²) -( 1/x²) - 2(cos2x)
f'(x) = 12x⁵ + 12x³ - 12x² - (1/x²) - 2cos2x
Similarly:
f''(x) = 60x⁴ + 36x² - 24x + (2/x³) + 4sin2x
f'''(x) = 240x³ + 72x - 24 - (6/x⁴) + 8cos2x
Rearrange:
f'''(x) - 240x³ +72x - (6/x⁴) + 8cos2x - 24
f''''(x) = 720x² + 72 + (24/x⁵) - 16sin2x
Rearrange:
f''''(x) = 720x² + (24/x⁵) - 16sin2x +72
2[(7 - 10)^2 + 5]^2
2[(-3)^2 + 5]^2
2[(9 + 5)]^2
2[(14)^2]
2(196)
392
Answer:
7 square units
Step-by-step explanation:
A = 7 x 2 x 1/2
A = 14 x 1/2
A = 7
Hope that helps!
