Let's solve your equation step-by-step.<span><span><span>
2/3</span><span>(<span><span>3x</span>+1</span>)</span></span>=5</span>
Step 1: Simplify both sides of the equation.<span><span><span>
2/3</span><span>(<span><span>3x</span>+1</span>)</span></span>=5</span><span>
Simplify: (Show steps)</span><span><span><span>
2x</span>+<span>2/3</span></span>=5</span>
Step 2: Subtract 2/3 from both sides.<span><span><span><span>
2x</span>+<span>2/3</span></span>−<span>2/3</span></span>=<span>5−<span>2/3</span></span></span><span><span>
2x</span>=<span>13/3</span></span>
Step 3: Divide both sides by 2.<span><span><span>
2x/</span>2</span>=<span><span>13/3/</span>2</span></span><span>
x=<span>13/6</span></span>
Answer:<span>
x=<span>13/<span>6</span></span></span>
Answer:
6, 12, 18, 24, 30, 36, etc.
Answer:
49
Step-by-step explanation:
43 +4 make sure you add them
47 +2
__
49
Answer: 875.5x
Step-by-step explanation:
Hello,
x^2-y^2=(x+y)(x-y)
x^3-y^3=(x-y)(x²+xy+y²)
Let's use Horner's division
.........|a^3|a^2.|a^1..........|a^0
.........|1....|5....|6..............|8....
a=p...|......|p....|5p+p^2....|6p+5p^2+p^3
----------------------------------------------------------
.........|1....|5+p|6+5p+p^2|8+6p+5p^2+p^3
The remainder is 8+6p+5p^2+p^3 or 8+6q+5q^2+q^3
Thus:
8+6p+5p^2+p^3 = 8+6q+5q^2+q^3
==>p^3-q^3+5p^2-5q^2+6p-6p=0
==>(p-q)(p²+pq+q²)+5(p-q)(p+q)+6(p-q)=0
==>(p-q)[p²+pq+q²+5p+5q+6]=0 or p≠q
==>p²+pq+q²+5p+5q+6=0
And here, Mehek are there sufficients explanations?
