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3 years ago

Solve the system of equations. -5x+2y=9 y=7x

Mathematics

2 answers:

posledela3 years ago

6 0

Answer:

x = 1

Step-by-step explanation:

Substitute y with 7x.

-5x + 2(7x) = 9

Solve parentheses.

-5x + 14x = 9

Combine like terms.

9x = 9

Now solve the equation.

9x = 9

/9 /9

-----------

x = 1

Law Incorporation [45]3 years ago

4 0

Answer:

uuuuuuuuuuum

Step-by-step explanation:

maybe it's...

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4 years ago

Read 2 more answers

<img src="https://tex.z-dn.net/?f=%20%28%7B%20%7Bx%7D%5E%7B2%7D%20%20-%204%7D%29%5E%7B5%7D%20%28%20%7B4x%20-%205%7D%29%5E%7B4%7D

Makovka662 [10]

Let $u=x^2-4$ and $v=4x-5$ . By the product rule,

$\dfrac{\mathrm d(u^5v^4)}{\mathrm dx}=\dfrac{\mathrm d(u^5)}{\mathrm dx}v^4+u^5\dfrac{\mathrm d(v^4)}{\mathrm dx}$

By the power rule, we have $(u^5)'=5u^4$ and $(v^4)'=4v^3$ , but $u,v$ are functions of $x$ , so we also need to apply the chain rule:

$\dfrac{\mathrm d(u^5)}{\mathrm dx}=5u^4\dfrac{\mathrm du}{\mathrm dx}$

$\dfrac{\mathrm d(v^4)}{\mathrm dx}=4v^3\dfrac{\mathrm dv}{\mathrm dx}$

and we have

$\dfrac{\mathrm du}{\mathrm dx}=2x$

$\dfrac{\mathrm dv}{\mathrm dx}=4$

So we end up with

$\dfrac{\mathrm d(u^5v^4)}{\mathrm dx}=10xu^4v^4+16u^5v^3$

Replace $u,v$ to get everything in terms of $x$ :

$\dfrac{\mathrm d((x^2-4)^5(4x-5)^4)}{\mathrm dx}=10x(x^2-4)^4(4x-5)^4+16(x^2-4)^5(4x-5)^3$

We can simplify this by factoring:

$10x(x^2-4)^4(4x-5)^4+16(x^2-4)^5(4x-5)^3=2(x^2-4)^4(4x-5)^3\bigg(5x(4x-5)+8(x^2-4)\bigg)$

$=2(x^2-4)^4(4x-5)^3(28x^2-57)$

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3 years ago

(Will give brainliest if asked for)

GarryVolchara [31]

A. x <= -12

<u>Explanation:</u>

-3x >= 36

-x >= 36/ 3

-x > = 12

x < = -12

When the negative sign is shifted then the greater than equal to sign reverses to less than equal to.

Therefore, x <= -12

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4 years ago