Question

Ax^2+ay^2–bx^2–by^2+b-a

Answer 1

$ax^2+ay^2-bx^2-by^2+b-a$
=$a(x^2+y^2)-b(x^2+y^2)+b-a$
=$(x^2+y^2)(a - b)+b-a$
=$(x^2+y^2)(a - b)-(a - b)$
=$(a - b)(x^2+y^2 -1)$

Answer 2

First, let's factor out the coefficient a. 

We have 

$ax^2+ay^2-bx^2-by^2+b-a$

$a(x^2+y^2-1)-bx^2-by^2+b$

Next, let's factor out the coefficient b.

$a(x^2+y^2-1)-b(x^2-y^2+1)$

Using the common factor $(x^2+y^2-1)$, we can rewrite as 

$(a-b)(x^2+y^2-1)$