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pychu [463]
3 years ago
6

In what quradrant does the terminal side of 0 lie when tan 0 < 0 and sin 0 < 0

Mathematics
1 answer:
Pie3 years ago
6 0

Answer:

Step-by-step expla0000000000000000000000000nation:

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Write an algebraic expression with the constant 7 and the variable y
77julia77 [94]
Here are a few algebraic expressions that include
the constant ' 7 ' and the variable 'y' :

7y

2y + 7

(y + 3) · (y - 7)

7 sin(y)

7x² +43z - 0.1y

√7 / y

19 y⁷
6 0
3 years ago
Given an IVP
MrRa [10]

Answer:

Step-by-step explanation: see attachment below

6 0
2 years ago
Please help me with this
SVEN [57.7K]
You can use 1 of 2 methods to solve this problem. You can either solve it traditionally or by just looking at it (you don't necessarily need to convert it to scientific notation to find the answer).

{METHOD 1}- Traditional Method

Scientific Notation is just another way of writing REALLY BIG or REALLY SMALL numbers in a simplified manor

Let's take 232,000,000 for instance

First you want to find your decimal number. Your decimal number has to be Greater than 1 and less than 10.

In this case your decimal number will be 2.32

Then let's could how many decimal places are to the RIGHT of 2.32
Keep in mind that if the number is very small you have to count the decimal places to the LEFT


{METHOD 2}

If you look at 232,000,000 and 2,320,000,000 you can tell that 2,320,000,000 is longer just by looking at it, so you can determine that ....

232,000,000 = 2.32E8
2,320,000,000=2.32E9

Using the same method you can solve the last two.

0.00000431 is a larger number than 0.000000000000431. So you can then determine that.....

0.00000431= 4.31E-6
0.000000000000431=4.31E-13

3 0
3 years ago
Find the range of the function represented by the list of ordered pairs below.
balandron [24]
What????????????? Im not speake inglês
7 0
2 years ago
In how many ways can a committee of five women and four men be formed from a group of seven women and seven men?
vekshin1
Number of combinations of 5 women from 7  = 7C5 =  7*6 / 2 = 21
for men its 7C4  = 7*6*5 / 3*2 =  35

Total number of ways = 21*35  = 735
6 0
3 years ago
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