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g100num [7]
3 years ago
9

Compute the selling price of a sports drink that has a cost of $1.25 per item. The store needs to generate a profit of $0.50 per

item.
Mathematics
1 answer:
luda_lava [24]3 years ago
7 0

Answer:

The selling price would be \$1.75.

Step-by-step explanation:

We have been given that a sports drink has a cost of $1.25.

We need to figure out the selling price of the sports drink so that the store is able to generate a profit of $0.50 per drink.

We know that profit is found by subtracting the cost of an item from selling price of the item. Therefore, selling price of the item can be found by adding the profit to the cost.

Therefore, the required selling price of the sports drink would be:

\$1.25+\$0.50=\$1.75

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A pool had 10 1/2 gallons of water in it Jake and his friend splashed g gallons of water out of the pool. There are 7 7/8 gallon
kolezko [41]

Answer: 6/625 gallons of water wa splashed out of the pool

Step-by-step explanation:

Total number of gallons of water in the pool was 10 1/2. Converting to improper fraction, it becomes

21/2 gallons.

Jake and his friend splashed g gallons of water out of the pool. There are 7 7/8 gallons still left in the pool. Converting 7 7/8 to improper fraction, it becomes

63/8 gallons

This means that

g + 63/8 = 21/2

g = 21/2 - 63/8 = (84 - 63)/8

g = 21/8 = 2.625 gallons

3 0
4 years ago
Find the difference between the sum of all even numbers and the sum of all odd numbers from 0 through 1000
Anna007 [38]
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3 years ago
Determine whether each figure creates the conditions to form a unique triangle, more than one triangle, or no triangle.
frutty [35]

Answer:

im like 95% sure its a unique triangle

Step-by-step explanation:

8 0
3 years ago
What is the perimeter of a triangle with sides<br> 11 inches, 5 inches, and 12 inches in length?
natulia [17]

Answer: 28 in.

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
A second particle, Q, also moves along the x-axis so that its velocity for 0 £ £t 4 is given by Q t cos 0.063 ( ) t 2 v t( ) = 4
Vladimir79 [104]

Answer:

The time interval when V_Q(t) \geq 60  is at  1.866 \leq t \leq 3.519

The distance is 106.109 m

Step-by-step explanation:

The velocity of the second particle Q moving along the x-axis is :

V_{Q}(t)=45\sqrt{t} cos(0.063 \ t^2)

So ; the objective here is to find the time interval and the distance traveled by particle Q during the time interval.

We are also to that :

V_Q(t) \geq 60    between   0 \leq t \leq 4

The schematic free body graphical representation of the above illustration was attached in the file below and the point when V_Q(t) \geq 60  is at 4 is obtained in the parabolic curve.

So, V_Q(t) \geq 60  is at  1.866 \leq t \leq 3.519

Taking the integral of the time interval in order to determine the distance; we have:

distance = \int\limits^{3.519}_{1.866} {V_Q(t)} \, dt

= \int\limits^{3.519}_{1.866} {45\sqrt{t} cos(0.063 \ t^2)} \, dt

= By using the Scientific calculator notation;

distance = 106.109 m

4 0
3 years ago
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