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3 years ago

Let f(t)=(t+4)^2 let f(t)=13

Mathematics

2 answers:

Ede4ka [16]3 years ago

4 0

Square 17. (13+4)^2=289.

Kipish [7]3 years ago

3 0

Answer:

very confused in this question

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suppose that a biologist is watching a trail known for wildebeest migration. During the first minute, 24 wildebeests migrated pa

Monica [59]

Answer:

=1050 wildebeests

Step-by-step explanation:

We can form an arithmetic series for the wildebeest migration.

Sₙ=n/2(2a+(n-1)d) where n is the number of terms, d is the common difference and a is the first term.

a=24

n=20

d=3

Sₙ=(20/2)(2(24)+(20-1)3)

Sₙ=10(48+57)

=1050 wildebeests

6 0

4 years ago

(25) Points please help will pick someone has the brainliest if right!

dem82 [27]

Answer:

D) 80

Step-by-step explanation:

Your answer is 80 because to find median you must Add up all of the numbers and divide by the number of numbers in the data set. The median is the central number of a data set. Arrange data points from smallest to largest and locate the central number. This is the median. Which I did and got 80 Your welcome

Hope this helped if it did plz give me brainiest Thanks <3

6 0

4 years ago

The data below shows the selling price (in hundred thousands) and the list price (in hundred thousands) of homes sold. Construct

fredd [130]

Answer:

Since the calculated t= 7.8120 falls in the critical region ≥ 2.306 we reject H0 and conclude that there is a linear correlation between the two variables.

Step-by-step explanation:

We see that r²= 0.981 and r= 0.995 from the figure .

The P- value is less than 0.05 which indicates that the two variables are linearly correlated.

Set up the hypothesis as

H0: β= 0 i.e the two variables X and Y are not related

Ha: β≠0 i.e the two variables are related

The significance Level is set at ∝=0.05

The test statistic , if H0 is true is

t= b/sb

where sb² = s²yx / ∑( x-x`)² = ∑( y-y`)²/n-2 ∑( x-x`)²

assuming that the distribution of Yi for each Xi is normal with the same mean and the same standard deviation , the statistic t conforms to the Student's t distribution with n-2= 8 degrees of freedom

(X - x`)2 (X - x`)(Y - y`) (Y - y`)2

265.69 259.17 15.9²=252.81

7174.09 6953.87 -82.1²=6740.41

75.69 87.87 -10.1=102.01

2052.09 1671.57 36.9²=1361.61

4529.29 5848.37 86.9²=7551.61

8335.69 7294.87 79.9²=6384.01

4998.49 5380.27 -76.1²=5791.21

1069.29 1016.97 -31.1=967.21

1043.29 1159.57 35.9²=1288.81

3102.49 3124.77 -56.1²=3147.21

SS: 32646.1 SP: 32797.3 33,586.9

Sum of X = 3877

Sum of Y = 3991

Mean X = 387.7

Mean Y = 399.1

Sum of squares (SSX) = 32646.1

Sum of products (SP) = 32797.3

b = SP/SSX = 32797.3/32646.1 = 1.00463

a = Y` - bX `= 399.1 - (1*387.7) = 9.60437

Syx= √∑(y-y`)²/n-2= 33,586.9/8= 4198.3625

sb= syx/ √∑(x-x`)²=4198.3625/32646.1 =0.12860

Putting the values in the regression equation

ŷ = bX + a

ŷ = 1.00463X + 9.60437

The critical region is t ≥ t (0.025) (8)= 2.306

t= b/ sb= 1.00463/ 0.12860=7.8120

Since the calculated t= 7.8120 falls in the critical region ≥ 2.306 we reject H0 and conclude that there is a linear correlation between the two variables.