What is y−4=−2(x+7) written in standard form?

Mathematics

2 answers:

omeli [17]4 years ago

4 0

Y=2x+18

Hope that helps!

nirvana33 [79]4 years ago

3 0

The standard form of a linear equation is $ax+by=c$ , where a, b, and c are numbers.

You are given $y-4=-2(x+7)$ . We need to start by expanding and simplifying.

$y-4=-2x-14\\y=-2x-14+4\\2x+y=-10$

Some teachers, including mine when I took Algebra 1, require that you find integers (whole numbers) for a, b, and c, and that a be positive. Here, we are fine.

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Solve each equation. Check your solution.<br><br><br> 3x 32 = 7x + 28

skad [1K]

Answer:

x= 28 /89

Step-by-step explanation:

3x(32)=7x+28

Step 1: Simplify both sides of the equation.

96x=7x+28

Step 2: Subtract 7 from both sides.

96x 7x+28

−7 −7

89x=28

Step 3: Divide both sides by 89.

89x /89 = 28 /89

6 0

3 years ago

Is the inverse of a symmetric matrix also symmetric?

Ahat [919]

Yes, the inverse of a symmetric matrix is also symmetric.

Take the symmetric matrix A, we have:

$AA^{-1} = I$

and

$I^{T} = I$

This gives:

$(AA^{-1})^{T} = AA^{-1}$

Using the properties:

$AA^{-1} = A^{-1}A$ and $(AA^{-1})^{T} = (A^{-1})^{T}A^{T}$

We get:

$(A^{-1})^{T}A^{T} = A^{-1}A$

Since $A^{T} = A$ , we can perform the substitution to get:

$(A^{-1})^{T}A = A^{-1}A$

Multiplying by $A^{-1}$ on both sides:

$(A^{-1})^{T}AA^{-1} = A^{-1}AA^{-1}$

$(A^{-1})^{T}I = A^{-1}I$

$(A^{-1})^{T} = A^{-1}$

Proving that the inverse of a symmetric matrix is also symmetric.

7 0

3 years ago

Help with this please?....:)<br>

marusya05 [52]

Answer:

200. 96 cm^2

Step-by-step explanation:

If the area of a circle is $\pi$ $r^{2}$