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mars1129 [50]
3 years ago
7

Find all points having an x coordinate of 5 whose distance from the point (2,2) is 5.

Mathematics
1 answer:
stepan [7]3 years ago
5 0

Answer:

(5,6) , (5,-2)

Step-by-step explanation:

Let the required point be P(5,y).

Its distance from (2,2) is 5 units.

So, (5-2)^{2} + (y-2)^{2} = 25.

So, 3^{2} +  (y-2)^{2} = 25.

  9 +  (y-2)^{2} = 25.

   (y-2)^{2} = 16

    Two cases are possible for now

case 1 : y-2 = 4 .

            y = 6

required point will be (5,6)

case 2 : y - 2 = -4.

              y = -2.

required point will be (5,-2).

Two points are possible : (5,6) , (5,-2).

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A bag contains 15 marbles. The probability of randomly selecting a green marble is 1/5. The probability of randomly selecting a
slava [35]

Answer:

6 blue marbles

Step-by-step explanation:

Given;

Total number of marbles N = 15

probability of randomly selecting a green marble

P(G) = 1/5

The probability of randomly selecting a green marble, replacing it, and then randomly selecting a blue marble P(G∩B) = 2/25

P(G∩B) = P(G) × P(B)

P(B) = P(G∩B) ÷ P(G)

The probability of selecting a blue marble

P(B) = 2/25 ÷ 1/5 = 2/5

The number of blue marbles N(B) = P(B) × N

N(B) = 2/5 × 15 = 6

There are 6 blue marbles

7 0
3 years ago
HELP PLEASE !!!!<br>A<br>B<br>C<br>D<br>E<br>???​
mario62 [17]

Answer:

A is the answer

Step-by-step explanation:

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4 0
3 years ago
Read 2 more answers
If PQ bisects CX at point J, and if JX = 4y and CJ = y+9 find y
MAXImum [283]
Since PQ bisects CX at point J, JX=CJ

4y=y+9
-y   -y
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3 0
4 years ago
Following from greatest to least 5 * 10 ^ 3 3.2 * 10 ^ 8 1.2 * 10 ^ 8 7 * 10 ^ 5
Zina [86]

Answer:

3.2*10^8>1.2*10^8>7*10^5>5*10^3

Step-by-step explanation:

5*10^3 = 5000

3.2*10^8=320000000

1.2*10^8=120000000

7*10^5=700000

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therefor

3.2*10^8>1.2*10^8>7*10^5>5*10^3

7 0
4 years ago
Find the values of x and y
cupoosta [38]

Answer:

Step-by-step explanation:

∠D = 90°

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7 0
3 years ago
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