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AnnZ [28]
2 years ago
11

5 1/6-3 5/6 i need help show how you got the answer

Mathematics
1 answer:
mojhsa [17]2 years ago
3 0

Assuming you mean mixed fractions, we have

5\dfrac{1}{6}=5+\dfrac{1}{6}

and

3\dfrac{5}{6}=3+\dfrac{5}{6}

So,

5\dfrac{1}{6}-3\dfrac{5}{6}=5+\dfrac{1}{6}-3-\dfrac{5}{6}=2-\dfrac{4}{6}=2-\dfrac{2}{3}

If you want to write this as a fraction, you have

2-\dfrac{2}{3} = \dfrac{6}{3}-\dfrac{2}{3}=\dfrac{4}{3}

If you want to write this as a mixed fraction, you have

2-\dfrac{2}{3}=1+\dfrac{3}{3}-\dfrac{2}{3}=1+\dfrac{1}{3}=1\dfrac{1}{3}

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Define a substitution method to solve the followingsysten of equation of y=2x-3, x+y=1
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→Step 1: Solve y = 2x - 3 for y

→Step 2: Substitute 2x - 3 for y in x + y = 1:

x + y = 1 

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