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AnnZ [28]
2 years ago
11

5 1/6-3 5/6 i need help show how you got the answer

Mathematics
1 answer:
mojhsa [17]2 years ago
3 0

Assuming you mean mixed fractions, we have

5\dfrac{1}{6}=5+\dfrac{1}{6}

and

3\dfrac{5}{6}=3+\dfrac{5}{6}

So,

5\dfrac{1}{6}-3\dfrac{5}{6}=5+\dfrac{1}{6}-3-\dfrac{5}{6}=2-\dfrac{4}{6}=2-\dfrac{2}{3}

If you want to write this as a fraction, you have

2-\dfrac{2}{3} = \dfrac{6}{3}-\dfrac{2}{3}=\dfrac{4}{3}

If you want to write this as a mixed fraction, you have

2-\dfrac{2}{3}=1+\dfrac{3}{3}-\dfrac{2}{3}=1+\dfrac{1}{3}=1\dfrac{1}{3}

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Solve for the hypotenuse in the right triangle shown.​
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Answer:

Square root of 34

Step-by-step explanation:

a^2 +b^2 =c^2

3^2 + 5^2 = 34

\sqrt{34}

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2 years ago
jenna's rectangular garden borders a wall. she buys 80 ft of fencing. what are the dimensions of the garden that will maximize i
FrozenT [24]

Answer:

The  dimensions are x =20 and y=20 of the garden that will maximize its area is 400

Step-by-step explanation:

Step 1:-

let 'x' be the length  and the 'y' be the width of the rectangle

given Jenna's buys 80ft of fencing of rectangle so the perimeter of the rectangle is    2(x +y) = 80

                         x + y =40

                               y = 40 -x

now the area of the rectangle A = length X width

                                                  A = x y

substitute 'y' value in above A = x (40 - x)

                                              A = 40 x - x^2 .....(1)

<u>Step :2</u>

now differentiating equation (1) with respective to 'x'

                                      \frac{dA}{dx} = 40 -2x     ........(2)

<u>Find the dimensions</u>

<u></u>\frac{dA}{dx} = 0<u></u>

40 - 2x =0

40 = 2x

x = 20

and y = 40 - x = 40 -20 =20

The dimensions are x =20 and y=20

length = 20 and breadth = 20

<u>Step 3</u>:-

we have to find maximum area

Again differentiating equation (2) with respective to 'x' we get

\frac{d^2A}{dx^2} = -2

Now the maximum area A =  x y at x =20 and y=20

                                        A = 20 X 20 = 400

                                         

<u>Conclusion</u>:-

The  dimensions are x =20 and y=20 of the garden that will maximize its area is 400

<u>verification</u>:-

The perimeter = 2(x +y) =80

                           2(20 +20) =80

                              2(40) =80

                              80 =80

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