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Wittaler [7]
2 years ago
8

SoMeonE plZ hAlp me lol

Mathematics
1 answer:
jeka942 years ago
3 0

C.√93


A=17

B=14

...........................

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A. x=51, y=63<br>b. x=77, y=63<br>c x=63, y=77<br>d x=77, y=65
vekshin1
The answer is b. x=77, y=63
5 0
3 years ago
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What is the equation of the circle with the given graph
AlexFokin [52]
(X+3)^2+(X-2)^2=9................
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3 years ago
If j and k are nonzero integers, which pair of points must lie in the same quadrant?
Marizza181 [45]
<h3>Answer:  Choice D.   (3j, 3k)  and (3/j, 3/k)</h3>

The slash indicates a fraction.

=============================================

Proof:

We'll need to consider 4 different cases.

-----------------------

Case (1): j > 0 and k > 0

If j > 0, then 3j > 0 and 3/j > 0

If k > 0, then 3k > 0 and 3/k > 0

The two points (3j, 3k) and (3/j, 3/k) are both in quadrant 1.

-----------------------

Case (2): j > 0 and k < 0

If j > 0, then 3j > 0 and 3/j > 0

If k < 0, then 3k < 0 and 3/k < 0

Points (3j, 3k) and (3/j, 3/k) are both in quadrant 4.

------------------------

Case (3): j < 0 and k > 0

If j < 0, then 3j < 0 and 3/j < 0

If k > 0, then 3k > 0 and 3/k > 0

Points (3j, 3k) and (3/j, 3/k) are in quadrant 3.

------------------------

Case (4): j < 0 and k < 0

If j < 0, then 3j < 0 and 3/j < 0

If k < 0, then 3k < 0 and 3/k < 0

Points (3j, 3k) and (3/j, 3/k) are in quadrant 4.

------------------------

For nonzero integers j and k, we've shown that Points (3j, 3k) and (3/j, 3/k) are in the same quadrant. This concludes the proof.

8 0
2 years ago
Read 2 more answers
The first three terms of a sequence are given. Round to the nearest thousandth (if
notka56 [123]

Answer:

Step-by-step explanation:

3,5,6,

a =3

d = 5-3 = 2

Tn= a+(n-1)d

T6= 3+(6-1)2 = 3 + (5)2 = 3 + 10 = 13

8 0
3 years ago
Please help i will give 10 points
lapo4ka [179]

Answer:

21 feet²

Step-by-step explanation:

To find the area of a composite figure, we can break the shape into pieces and solve for the area separately.

There are multiple ways to separate the figure, but for this explanation we will break it into two rectangles, 5×3 and 3×2.

The area of a rectangle can be found by multiplying the length and width of the shape. So for the left rectangle, we will multiply 5 by 3.

5 · 3 = 15

The area of our first rectangle is 15 ft².

Next, we will find the area of the right rectangle, by multiplying 3 by 2.

3 · 2 = 6

The area of the second rectangle is 6 ft².

Now we can add the areas, 15 and 6, together to find the total area.

15 + 6  = 21

The area of the figure is 21 ft².

I hope this helps ^^ Good luck ∩_∩

3 0
2 years ago
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