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3 years ago

ASAP what is 2617.99 rounded tenth?

Mathematics

2 answers:

kumpel [21]3 years ago

8 0

The answer is 2620 since the 1 is in the tenths place

Gwar [14]3 years ago

7 0

Answer:

2620

Step-by-step explanation:

The tenth place value is 2 places after the decimal so round off from there

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ahmed is sitting on a dock watching a float plane in a harbour. At a certain time, the plane is 350 m above the water and 470 m

Pavel [41]

Answer:

The angle of elevation of the plane measured from Ahmed is approximately 36.67°

Step-by-step explanation:

The given parameters of the float plane are;

The height of the float plane above the water, y = 350 m

The horizontal distance of the float plane from Ahmed, x = 470 m

Given that Ahmed is sitting on the dock, by the water, by trigonometric ratios, we have;

The height of the float plane, the distance of the plane from Ahmed and the line of sight forming the angle of elevation of the plane measured from Ahmed, form a right triangle

$tan\angle X = \dfrac{Opposite \ leg \ length}{Adjacent \ Leg\ length}$

Therefore

$tan(\theta) = \dfrac{y}{x}$

Where;

θ = The angle of elevation of the plane measured from Ahmed

y = The leg of the right triangle opposite the reference angle

x = The leg of the right adjacent to reference angle

Therefore;

θ = arctan(y/x) which gives;

θ = arctan(350/470) ≈ 36.67°

The angle of elevation of the plane measured from Ahmed, θ ≈ 36.67°.

8 0

3 years ago

Julia has correctly answered 35 questions from a test, which is 7/12 of the total. How many questions did the test have?

otez555 [7]

Answer:

There are 60 questions on the test

Step-by-step explanation:

Hope this helps :)

4 0

3 years ago

PLEASE HELP!<br>Calculate $40^{13} \pmod{85}.$

SVEN [57.7K]

In this type of calculations, we decompose 13 by checking the lowest powers of the base, that is 40. for example we check 40^2, or 40^3 and compare it to 85

Notice

40*40*40=64,000

so we check how many time does 85 fit into 64,000:

64,000/85=752.94

85*753=64,005; 64000-64,005=-5

this means that

$40^{3} =-5\pmod{85}$

thus

$40^{13} =40^{3*4+1}={(40^{3})}^{4}*40=(-5)^{4}*40 \pmod{85}=\\\\625*40\pmod{85}=(7*85+30)*40\pmod{85}=30*40\pmod{85}\\\\=1200\pmod{85}=(14*85+10)\pmod{85}=10\pmod{85}$

Answer: 10 (mod85)

Remark, the set of all solutions is:

{......-75, 10, 95, .....}, that is 85k +10

7 0

3 years ago

Harper has $15.00 to spend at her grocery store. She is going to buy bags of fruit that cost $4.75 each and one box of crackers

Andrej [43]

First write the inequality: 15 $\leq$ 4.75x +3.50

Then to solve, first subtract 3.50 from both sides to get:

11.50 $\leq$ 4.75x

Then divide by 4.75 to get 2.42, and since you can't buy .42 of a bag of fruit, you round down. So your final answer would be 2 bags of fruit.

7 0

3 years ago

Read 2 more answers

Babies born after 40 weeks gestation have a mean length of 52.2 centimeters (about 20.6 inches). Babies born one month early hav

Sveta_85 [38]

Answer:

a) $Z = -2.88$

b) $Z = -0.96$

c) 40 weeks gestation babies

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

a. Find the standardized score (z-score), relative to all U.S. births, for a baby with a birth length of 45 cm.

Here, we use $\mu = 52.2, \sigma = 2.5$ . So

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{45 - 52.2}{2.5}$

$Z = -2.88$

b. Find the standardized score of a birth length of 45 cm. for babies born one month early, using 47.4 as the mean.

Here, we use $\mu = 47.4, \sigma = 2.5$ . So

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{45 - 47.4}{2.5}$

$Z = -0.96$

c. For which group is a birth length of 45 cm more common?

For each group, the probability is 1 subtracted by the pvalue of Z.

Z = -2.88 has a lower pvalue than Z = -0.96, so for Z = -2.88 the probability 1 - pvalue of Z will be greater. This means that for 40 weeks gestation babies a birth length of 45 cm is more common.

3 0

3 years ago