Answer:
y=1
Step-by-step explanation:
20-18/6-4 = 2/2 = I
Hope this helped
Answer:
9
in²
Step-by-step explanation:
The area (A) of an equilateral triangle is calculated as
A = 
( s is the length of a side )
Here s = 6, thus
A = 
= 
= 9 in²
Using Laplace transform we have:L(x')+7L(x) = 5L(cos(2t))sL(x)-x(0) + 7L(x) = 5s/(s^2+4)(s+7)L(x)- 4 = 5s/(s^2+4)(s+7)L(x) = (5s - 4s^2 -16)/(s^2+4)
=> L(x) = -(4s^2 - 5s +16)/(s^2+4)(s+7)
now the boring part, using partial fractions we separate 1/(s^2+4)(s+7) that is:(7-s)/[53(s^2+4)] + 1/53(s+7). So:
L(x)= (1/53)[(-28s^2+4s^3-4s^2+35s-5s^2+5s)/(s^2+4) + (-4s^2+5s-16)/(s+7)]L(x)= (1/53)[(4s^3 -37s^2 +40s)/(s^2+4) + (-4s^2+5s-16)/(s+7)]
denoting T:= L^(-1)and x= (4/53) T(s^3/(s^2+4)) - (37/53)T(s^2/(s^2+4)) +(40/53) T(s^2+4)-(4/53) T(s^2/s+7) +(5/53)T(s/s+7) - (16/53) T(1/s+7)
The question is incomplete. Here is the complete question
It was estimated that because of people switching to Metro trains about 33000 of CNG 3300 tons of diesel and 21000 tons of petrol was saved by the end of year 2007 (I) find a fraction of the quantity of diesel saved to the quantity of petrol saved (ii) find the quantity of cng to the quantity of diesel saved
Answer:
(I) 11/70
(II) 1/10
Step-by-step explanation:
Metro trains contain 330,000 tons of CNG
3300 tons of diesel was saved
21000 tons of petrol was saved at the end of 2007
(I) The fraction of the quantity of diesel saved to the quantity of petrol saved can be calculated as follows
= 3300/21000
= 11/70
(II) The fraction of the quantity of CNG saved to the quantity of diesel can be calculated as follows
= 3300/33000
= 1/10
