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omeli [17]
3 years ago
5

Gabby opened a savings account and deposited $800.00 as principal. The

Mathematics
1 answer:
Yuri [45]3 years ago
7 0

Answer:

Use the formula A = p x e^(rate x year), we have:

A = 800 x 2.71828^[(13/100) x 1] = 991.06 = ~911.1 dollar

Hope this helps!

:)

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1) Jose saves $9/ week.He wants to buy a backpack that cost $45. If he save his money for 7 weeks, Would he be able to afford th
Alja [10]
1. Yes he would be able to but the back pack and he would actually have 18 to spare. Explanation- he saves $9 a week so if he saves for 7 weeks then he will have $63 but since he only needed 45 he will have 18 to spare
2. Since they have 65.50 but need to have 180 then u could just subtract 180 from 65.50 so they would 114.5 more dollars
3. Since lee scored 4 FEWER this tells us that micheal has more points so you would just add 4 to micheals total of points which would give you that micheal had 22 points
3 0
3 years ago
Read 2 more answers
1/5 PART OF A POLE IS INSIDE THE MUD, 2/3 PART IS INSIDE THE WATER AND THE REMAINING LENGTH OF 10m IS ABOVE THE SURFACE OF THE W
Andrei [34K]

Answer:

1/ 5 and 2/3

cross multiple

example

1                2       =       10

/        x       /         =      /

5                 3                3

= 10/3

so it's 3 1/3 + 10 Mm

so may guess is

13.3333 infinite  or 13.34 M

Dont know if its right but good luck

8 0
2 years ago
Read 2 more answers
Jessie draws triangle ABC on a coordinate grid. The slope of line segment AB is Jessie then transforms triangle
balu736 [363]

Answer:

1) Supports Jessie's Claim

2) Does Not Support Jessi's Claim

3) Supports Jessie's Claim

4) Does Not Support Jessi's Claim

Step-by-step explanation:

The given transformations are;

1) Rotation of 180° around the origin

For a rotation of 180° around the origin, either clockwise or anti clockwise, for a given coordinate of the preimage (x, y), the coordinate of the image is (-x, -y)

Therefore, whereby the slope of the preimage, given two points (0, 0) and (2, 2), = (2 - 0)/(2 - 0) = 1

For the image with the points (0, 0) and (-2, -2), we have;

(-2 - 0)/(-2 - 0) = 1

Therefore, the slope of the preimage and the image are equal

Therefore, supports Jessie's Claim

2) For a reflection across the line y = 2, we have

We note that the line y = 2 is parallel to the x-axis

For a reflection across the x-axis, for a preimage (x, y), we have the coordinates of the image (x, -y)

However for the reflection across the line y = 2, we have;

For a preimage, (x, y), the coordinate of the image is (x, -y+4)

Given two points, of the preimage (0, 0) and (2, 2), we have the image given as (0, 4) and (2, -2 + 4) = (2, 2);

The slope of the preimage is (2 - 0)/(2 - 0) = 1

The slope of the image is (2 - 4)/(2 - 0) = -1

The slope of the line of the preimage and the image are different

Therefore, does Not Support Jessi's Claim

3) For a translation up 1.25 units, we note that the difference in the y and x values of the coordinates of the preimage and the image will be equal when finding the slope, and therefore, the slope of the figure of the preimage and the slope of the figure of the image will be equal

Therefore, supports Jessie's Claim

4) For a reflection across the x-axis, a point on the preimage, with coordinates (x, y) will form a point on the image with coordinates (x, - y)

For a preimage with points (0, 0) and (2, 2), we have the image as (0, 0) and (2, -2)

The slope of the preimage is (2 - 0)/(2 - 0) = 1

The slope of the image is (-2 - 0)/(2 - 0) = -1

The slope of the line of the preimage and the image are different

Therefore, does Not Support Jessi's Claim

6 0
3 years ago
Find the average of 2m,20cm and 95cm give your answer in cm​
stepan [7]

Answer:

The average is:

105 cm

Step-by-step explanation:

1 m = 100cm

2m = 2*100 = 200cm

then:

(200 + 20 + 95)/3 = 315/3 = 105cm

3 0
3 years ago
HEEELLLPPP!!!!!!!!! PLEEAASEEE!!!!!!!!
Ksivusya [100]

Answer:

Step-by-step explanation:

17.  (a^{m})^{n}=a^{m*n}\\\\a^{m}*a^{n}=a^{m+n}\\\\-3k^{2}*(4k^{5})^{3}=-3k^{2}*4^{3}*k^{5*3}\\\\ = -3k^{2}*64*k^{15}\\\\= (-3)*64*k^{2+15}\\\\= - 192k^{17}

19. \dfrac{a^{m}}{a^{n}}=a^{m-n}\\\\\\\dfrac{(-7p^{4})*(-8p^{5})}{2p^{3}}= \dfrac{(-7)*(-8)*p^{4}*p^{5}}{2p^{3}}\\\\\\=(-7)*(-4)*p^{4+5-3} \\\\= 28p^{6}\\

20)\dfrac{15a^{16}b^{11}}{(3a^{4}b^{2})^{3}}=\dfrac{15a^{16}b^{11}}{3^{3}*a^{4*3}*b^{2*3}}\\\\\\=\dfrac{15a^{16}b^{11}}{27*a^{12}*b^{6}}\\\\=\dfrac{5*a^{16-12}*b^{11-6}}{9}\\\\\\=\dfrac{5a^{4}b^{5}}{9}

4 0
2 years ago
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