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3 years ago

3x² + 22x + 35 Factor the trinomial Help guys asp!!

Mathematics

1 answer:

Levart [38]3 years ago

5 0

Answer:

(x + 5)(3x + 7)

Step-by-step explanation:

Given

3x² + 22x + 35

Consider the factors of the product of the x² term and the constant which sum to give the coefficient of the x- term

product = 3 × 35 = 105 and sum = 22

The factors are + 15 and + 7

Use these factors to split the x- term

= 3x² + 15x + 7x + 35 ( factor the first/second and third/fourth terms )

= 3x(x + 5) + 7(x + 5) ← factor out (x + 5) from each term

= (x + 5)(3x + 7) ← in factored form

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Answer:

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Step-by-step explanation:

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3 years ago

Read 2 more answers

Find the 53rd term of the arithmetic sequence<br> 27,11, -5

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Answer:

The 53rd term of this arithmetic sequence is -805.

Step-by-step explanation:

The general rule of an arithmetic sequence is the following:

$a_{n+1} = a_{n} + d$

In which d is the common diference between each term, that is, $d = a_{3} - a_{2} = a_{2} - a_{1}$ .

To find the nth term of the sequence, this equation can be written as:

$a_{n} = a_{1} + (n-1)d$

27,11, -5

So $a_{1} = 27, a_{2} - a_{1} = 11 - 27 = -16[/tex[tex]a_{n} = a_{1} + (n-1)d$

$a_{53} = a_{1} + (52)d = 27 + 52*(-16) = -805$

The 53rd term of this arithmetic sequence is -805.

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Step-by-step explanation:

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