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astraxan [27]
2 years ago
10

What is (-5/8) x (2/3)?

Mathematics
2 answers:
valentina_108 [34]2 years ago
5 0
-5/8 * 2/3=

-5/8= -0.625
2/3=0.666666667

So multiply them together, and you get...

-0.416666667

Or -0.42

Or in simplified form... -5/12

Hope this helps you!
Let me know!
frozen [14]2 years ago
3 0
-5/12 would be the answer
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Smith chose the underlined words for a reason. What
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She wanted to persuade others that women should not ride bicycle

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Question 5- Please help. Using a piece of pizza explain what arc length and area of the sector mean in two to three sentences.
pickupchik [31]

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You'd have to look at the size of the pizza and then measure the size of the arc for each slice. The slice of pizza is how many topping is on it. The sector is how much pizza you are consuming from the center to the crust. The arc is the crust around the pizza.

3 0
3 years ago
A music app charges $2 to download the app plus $1.29 per song downloaded. Write and solve a linear equation to find the total c
Gennadij [26K]

Answer:

1.29(30) +2

Step-by-step explanation:

First you do 1.29 times 30 that equals 38.7. Then you do 38.7 + 2 and you get 40.7. This means that the total cost is $40.70.

6 0
3 years ago
Construct a 90% confidence interval for μ1-μ2 with the sample statistics for mean calorie content of two​ bakeries' specialty pi
DIA [1.3K]

Answer:

The 90% confidence interval for the difference in mean (μ₁ - μ₂) for the two bakeries is; (<u>49</u>) < μ₁ - μ₂ < (<u>289)</u>

Step-by-step explanation:

The given data are;

Bakery A

\overline x_1<em> </em>= 1,880 cal

s₁ = 148 cal

n₁ = 10

Bakery B

\overline x_2<em> </em>= 1,711 cal

s₂ = 192 cal

n₂ = 10

\left (\bar{x}_1-\bar{x}_{2}  \right ) - t_{c}\cdot \hat \sigma \sqrt{\dfrac{1}{n_{1}}+\dfrac{1}{n_{2}}}< \mu _{1}-\mu _{2}< \left (\bar{x}_1-\bar{x}_{2}  \right ) + t_{c}\cdot \hat \sigma \sqrt{\dfrac{1}{n_{1}}+\dfrac{1}{n_{2}}}

df = n₁ + n₂ - 2

∴ df = 10 + 18 - 2 = 26

From the t-table, we have, for two tails, t_c = 1.706

\hat{\sigma} =\sqrt{\dfrac{\left ( n_{1}-1 \right )\cdot s_{1}^{2} +\left ( n_{2}-1 \right )\cdot s_{2}^{2}}{n_{1}+n_{2}-2}}

\hat{\sigma} =\sqrt{\dfrac{\left ( 10-1 \right )\cdot 148^{2} +\left ( 18-1 \right )\cdot 192^{2}}{10+18-2}}= 178.004321469

\hat \sigma ≈ 178

Therefore, we get;

\left (1,880-1,711  \right ) - 1.706\times178 \sqrt{\dfrac{1}{10}+\dfrac{1}{18}}< \mu _{1}-\mu _{2}< \left (1,880-1,711  \right ) + 1.706\times178 \sqrt{\dfrac{1}{10}+\dfrac{1}{18}}

Which gives;

169 - \dfrac{75917\cdot \sqrt{35} }{3,750} < \mu _{1}-\mu _{2}< 169 + \dfrac{75917\cdot \sqrt{35} }{3,750}

Therefore, by rounding to the nearest integer, we have;

The 90% C.I. ≈ 49 < μ₁ - μ₂ < 289

4 0
3 years ago
Please help me solve this
sp2606 [1]

Answer:

-1

Step-by-step explanation:

Let's use the formula!

6 - 3 = 3

-4 - (-1) = -3

The slope is -3/3 or -1

5 0
2 years ago
Read 2 more answers
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