An exponential equation is represented as:
, where b represents rate
- Exponential growth:
,
and 
- Exponential decay:

- Neither:

An exponential equation is said to represent growth, if the rate is greater than 1, while it represents decay if the rate is less than 1.
This means that:
,
and
represent exponential growth because 5, 4.2 and 1.3 are greater than 1
Also,
represents exponential decay because 0.28 is less than 1
While
is not an exponential function
Read more about exponential functions at:
brainly.com/question/11487261
Answer:

Step-by-step explanation:
Here is the full question
A standard piece of paper is 0.05 mm thick. Let's imagine taking a piece of paper and folding the paper in half multiple times. We'll assume we can make "perfect folds," where each fold makes the folded paper exactly twice as thick as before - and we can make as many folds as we want.
Write a function g that determines the thickness of the folded paper (in mm) in terms of the number folds made, n. (Notice that g(0) 0.05,)

The function g has an inverse. The function g⁻¹ determines the number of folds needed to give the folded paper a thickness of t mm. Write a function formula for g⁻¹).
<u>SOLUTION:</u>
If we represent g(n) with t;
Then

Taking logarithm of both sides; we have :

Answer:
1. b. 2. a. 3. a.
Step-by-step explanation:
1. (f + g)x = f(x) + g(x)
= x^2 + 2x + 4
(f + g)(-1) = (f + g)(x) where x = 1 so it is
(-1)^2 + 2(-1) + 4
= 1 - 2 + 4
= 3.
2. We find (f o g)(x) by replacing the x in f(x) by g(x):
= √(x + 1) and
(f o g)(3) = √(3 + 1)
= √4
= 2.
3. (f/g) c = f(x) / g(x)
= (x - 3)/(x + 1)
The domain is the values of x which give real values of (f/g).
x cannot be - 1 because the denominator x + 1 = -1+1 = 0 and dividing by zero is undefined. So x can be all real values of x except x = -1.
The domain is (-∞, -1) U (-1, ∞)
Answer:
see below
Step-by-step explanation:
If suffices to look at the last term. It must simplify to 4/(3w²), so the exponents of z must match in numerator and denominator, and the ratio of constants must reduce to 4/3.
The exponents of z have the right values in choices B and D, but the ratio of constants only matches in choice D. Looking at the rest of choice D, we see that we can factor 6w²z² from both numerator and denominator, then factor 2 from the remaining numerator to make it match the desired form.
