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Fittoniya [83]
2 years ago
14

A number greater than 40 whose prime factorization contain 3 prime numbers that do not repeat

Mathematics
1 answer:
BartSMP [9]2 years ago
7 0

How about 105 ?

In factored form, it's  =  1 x 3 x 5 x 7 .

In fact, I think that's the smallest one that's less than 40.

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Given the diagram below find the value of x if the area is 21 aquare meters
Oksanka [162]

Answer:

The answer is <u><em>7</em></u>!

Step-by-step explanation:

(x-4) (x) = 21, x^2 - 4x = 21, x^2 - 4x - 21 = 0, (x - 7) (x + 3) = 0, x = 7 and -3; x can't be negative so the answer is 7!

x = 7 and x - 4 (other side) = 3

5 0
2 years ago
Mike is a car salesman. He earns $200 for every car he sells plus a 3% commission. If Mike sells 3 cars in one week for a total
Serhud [2]

<span>For every car Mike earns------------------ >$200 plus 3% commission</span>

 3 cars----------------- > $200*3+$32,343*0.03=600+970.29=$1570.29

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6 0
3 years ago
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Which of the following is the value of pq ? 2x+41
loris [4]

m pq = 2 Have a good day! sorrey if i'm wrong

8 0
3 years ago
Find the missing dimension of the prism. Round your answer to the nearest hundredth.
Nitella [24]

Answer:

x = 6.99in

Step-by-step explanation:

Given

l =2in

Volume = 72.66in^3

See attachment for prism

Required

Find x

The prism has a regular hexagon base

The base area is calculated as:

Base\ Area= \frac{3\sqrt 3}{2}l^2

This gives:

Base\ Area= \frac{3\sqrt 3}{2} * 2^2

Base\ Area= \frac{3\sqrt 3}{2} * 4

Base\ Area= 3\sqrt 3 * 2

Base\ Area= 6\sqrt 3

Side x represents the height.

So, we have:

Volume = Base\ Area*x

Make x the subject

x = \frac{Volume }{ Base\ Area}

x = \frac{72.66in^3}{6\sqrt 3 in^2}

x = \frac{72.66}{6\sqrt 3}in

x = \frac{12.11}{\sqrt 3}in

x = 6.99in --- approximated

6 0
3 years ago
Write the polar form of a complex number in standard form for <img src="https://tex.z-dn.net/?f=25%5Bcos%28%5Cfrac%7B5%5Cpi%20%7
Masja [62]

Answer:

Standard Complex Form  : -\frac{25\sqrt{3}}{2}+\frac{25}{2}i

Step-by-step explanation:

We want to rewrite this expression in standard complex form. Let's first evaluate cos(5π / 6). Remember that cos(x) = sin(π / 2 - x). Therefore,

cos(5π / 6) = sin(π / 2 - 5π / 6),

π / 2 - 5π / 6 = - π / 3,

sin(- π / 3) = - sin(π / 3)

And we also know that sin(π / 3) = √3 / 2. So - sin(π / 3) = - √3 / 2 = cos(5π / 6).

Now let's evaluate the sin(5π / 6). Similar to cos(x) = sin(π / 2 - x), sin(x) = cos(π / 2 - x). So, sin(5π / 6) = cos(- π / 3). Now let's further simplify from here,

cos(- π / 3) = cos(π / 3)

We know that cos(π / 3) = 1 / 2. So, sin(5π / 6) = 1 / 2

Through substitution we receive the expression 25( - √3 / 2 + i(1 / 2) ). Further simplification results in the following expression. <u>As you can see your solution is option a.</u>

-\frac{25\sqrt{3}}{2}+\frac{25}{2}i

7 0
3 years ago
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