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kenny6666 [7]
3 years ago
10

tania needs to buy at least 3 pounds of bananas. if she buys a bunch of bananas that weighs 42 ounces will she have enough? expl

ain
Mathematics
2 answers:
Butoxors [25]3 years ago
4 0

Answer:

I believe that you are asking if she buys a bunch of bananas that weigh 42 ounces, will she have enough (3 pounds).

We know that there are 16 ounces in a pound. So we multiply 3 x 16 to get 48. This means that we would need 48 ounces of bananas.

Tania only has 42 ounces, so she does not have enough bananas

Artyom0805 [142]3 years ago
4 0

Answer:

no

Step-by-step explanation:

1 pound = 16 ounces

42 ounces = 2.625 pounds

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First get a LCM (least common multiple) for 3, 5, and 2.

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Nearest cent- $1.43

Step-by-step explanation:

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3 years ago
What is the value of the expression below?<br><br> 1 3/4 divided by 1/2 minus (1 1/2)^3
kogti [31]

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1/8

Step-by-step explanation:

Simplify the following:

(1 + 3/4)/(1/2) - (1/2 + 1)^3

Hint: | Write (1 + 3/4)/(1/2) as a single fraction.

Multiply the numerator of (1 + 3/4)/(1/2) by the reciprocal of the denominator. (1 + 3/4)/(1/2) = ((1 + 3/4)×2)/1:

(3/4 + 1) 2 - (1/2 + 1)^3

Hint: | Put the fractions in 1 + 1/2 over a common denominator.

Put 1 + 1/2 over the common denominator 2. 1 + 1/2 = 2/2 + 1/2:

(1 + 3/4) 2 - (2/2 + 1/2)^3

Hint: | Add the fractions over a common denominator to a single fraction.

2/2 + 1/2 = (2 + 1)/2:

(1 + 3/4) 2 - ((2 + 1)/2)^3

Hint: | Evaluate 2 + 1.

2 + 1 = 3:

(1 + 3/4) 2 - (3/2)^3

Hint: | Put the fractions in 1 + 3/4 over a common denominator.

Put 1 + 3/4 over the common denominator 4. 1 + 3/4 = 4/4 + 3/4:

4/4 + 3/4 2 - (3/2)^3

Hint: | Add the fractions over a common denominator to a single fraction.

4/4 + 3/4 = (4 + 3)/4:

(4 + 3)/4×2 - (3/2)^3

Hint: | Evaluate 4 + 3.

4 + 3 = 7:

7/4×2 - (3/2)^3

Hint: | Express 7/4×2 as a single fraction.

7/4×2 = (7×2)/4:

(7×2)/4 - (3/2)^3

Hint: | In (7×2)/4, divide 4 in the denominator by 2 in the numerator.

2/4 = 2/(2×2) = 1/2:

7/2 - (3/2)^3

Hint: | Simplify (3/2)^3 using the rule (p/q)^n = p^n/q^n.

(3/2)^3 = 3^3/2^3:

7/2 - 3^3/2^3

Hint: | In order to evaluate 3^3 express 3^3 as 3×3^2.

3^3 = 3×3^2:

7/2 - (3×3^2)/2^3

Hint: | In order to evaluate 2^3 express 2^3 as 2×2^2.

2^3 = 2×2^2:

7/2 - (3×3^2)/(2×2^2)

Hint: | Evaluate 2^2.

2^2 = 4:

7/2 - (3×3^2)/(2×4)

Hint: | Evaluate 3^2.

3^2 = 9:

7/2 - (3×9)/(2×4)

Hint: | Multiply 2 and 4 together.

2×4 = 8:

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Hint: | Multiply 3 and 9 together.

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Hint: | Subtract the fractions over a common denominator to a single fraction.

28/8 - 27/8 = (28 - 27)/8:

(28 - 27)/8

Hint: | Subtract 27 from 28.

| 2 | 8

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| 0 | 1:

Answer: 1/8

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