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3 years ago

A line with slope 3.5 and y-intercept (0,4) Show work

Mathematics

2 answers:

kifflom [539]3 years ago

4 0

I believe it would be y = mx + b

So we have our slope, which is m. And we have a coordinate point (both x and y) (0,4) So now plug them all into the equation.

4 = 3.5(0) + b

4 = 0 + b

4 = b. Your answer for B would be 4.

So now your entire equation is y = 3.5x + 4

Hope this helped!

-TTL

kap26 [50]3 years ago

3 0

slope intercept form

y= mx+b

y = 3.5x +4

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Which of the following are solutions to the equation below?

sladkih [1.3K]

Answer:

$\mathrm{The\:solutions\:to\:the\:quadratic\:equation\:are:}$

$x=3,\:x=-\frac{1}{2}$

Step-by-step explanation:

considering the equation

$2x^2\:-\:4x\:-\:3\:=\:x$

solving

$2x^2\:-\:4x\:-\:3\:=\:x$

$2x^2-4x-3-x=x-x$

$2x^2-5x-3=0$

$\mathrm{For\:a\:quadratic\:equation\:of\:the\:form\:}ax^2+bx+c=0\mathrm{\:the\:solutions\:are\:}$

$x_{1,\:2}=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$

$\mathrm{For\:}\quad a=2,\:b=-5,\:c=-3:\quad x_{1,\:2}=\frac{-\left(-5\right)\pm \sqrt{\left(-5\right)^2-4\cdot \:2\left(-3\right)}}{2\cdot \:2}$

solving

$x=\frac{-\left(-5\right)+\sqrt{\left(-5\right)^2-4\cdot \:2\left(-3\right)}}{2\cdot \:2}$

$x=\frac{5+\sqrt{\left(-5\right)^2+4\cdot \:2\cdot \:3}}{2\cdot \:2}$

$x=\frac{5+\sqrt{49}}{2\cdot \:2}$

$x=\frac{5+7}{4}$

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also solving

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$x=\frac{5-\sqrt{\left(-5\right)^2+4\cdot \:2\cdot \:3}}{2\cdot \:2}$

$x=\frac{5-\sqrt{49}}{4}$

$x=-\frac{2}{4}$

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$\mathrm{The\:solutions\:to\:the\:quadratic\:equation\:are:}$

$x=3,\:x=-\frac{1}{2}$

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3 years ago

the legs of a right triangle have lengths of 28 meters and 21 meters. the hypotenuse has a lenght of 5x meters. what is the valu

Luba_88 [7]

From the Pythagorean Theorem, we know that a^2+b^2=c^2
28^2+21^2=(5x)^2
784+441=25x^2
1225=25x^2
49=x^2
x=7
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3 years ago

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kvv77 [185]

So a hack is we know that 20% times 5 =100% and 40 divided by 2=20 so

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g - 50 = g - 5c

5c = 50

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Substitute c in equation 1

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Answer:

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