Solve T=C(3 + AB) for A.
1 answer:
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Answer:
X-5Y-4Z+12=0
Step-by-step explanation:
Plan P1 = 3x-y+2z=1. with A=(1,1,2); B=(2,2,1); we must will find V1 from P1,
V1 =(3,-1,2) and AB = (2-1,2-1,1-2) = (1,1,-1) now we find V2 by vector product.
V2 =V1.X,AB =; (aplying sarrus method)
according to general plan formula a(X-Xo)+b(Y-Yo)+c(Z-Zo); V=(a,b,c)
V2=(-1,5,4) ; A=(1,1,2); so -(X-1)+5(Y-1)+4(z-2)=0 → -X+1+5Y-5+4Z-8=0 →
-X+5Y+4Z+1-5-8=0 → -X+5Y+4Z-12=0 (-1) → Plan equation X-5Y-4Z+12=0
Answer:
The answer to your question is: the first option
Step-by-step explanation:
The first option is correct
The coordinates of the rectangle are (-3,-1), (1,3), (3,1) and (-1,-3).
Draw the given rectangle as shown in the figure below.
Calculate the length of the rectangle as
a = √(4² + 4²) = 4√2
Calculate the width of the rectangle as
b = √(2² + (-2)²) = 2√2
Calculate the area of the rectangle as
A = a*b = (4√2) * (2√2) = 16
Answer: 16
Draw the given rectangle as shown in the figure below.
Calculate the length of the rectangle as
a = √(4² + 4²) = 4√2
Calculate the width of the rectangle as
b = √(2² + (-2)²) = 2√2
Calculate the area of the rectangle as
A = a*b = (4√2) * (2√2) = 16
Answer: 16