Neptune's distance from the sun is d₁ = 4.503 x 10⁹ km.
Mercury's distance from the sun is d₂ = 5.791 x 10⁷ km.
Calculate the number of times d₁ is greater than d₂.
Answer: 7.7759 x 10⁻¹ times
2/4 is equivalent to 1/16 and 1/128 if dived by 8 sections
8/8 is equivalent to 1/8 and 1/64 if dived by 8 sections
1/2 is equivalent to 1/16 and 1/128 if dived by 8 sections
3/4 is equivalent to 3/32 and 3/256 if dived by 8 sections
2/3 is equivalent to 1/12 and 1/98 if dived by 8 sections
Answer:
55.95 ft²
Step-by-step explanation:
Circumference formula: C = 2πr => r = C / (2π)
Area formula: A = πr²
Substituting C / (2π) for r in the above equation, we get:
C 47 ft
A = π( ----------- )² = π ( -------------- )²
2π (2π)
or ...
π(47 ft)² 2209 ft²
A = ---------------------- = -------------------- = 55.95 ft²
4π² 4(3.14159)²
Answer:
You must draw a right triangle and label the hypotenuse as 41 and the longest leg (horizontal in this case, since we are to determine the height) as 40. We do not know the height so call it h.
Now the Pythagorean (sp /) Theorem states that the square of the hyp. is equal to the sum of the squares of the two legs.
so, 41 ^ 2 = 40 ^ 2 + h ^ 2
41 ^ 2 = 1681 40 ^ 2 = 1600 Therefore h ^2 must be equal to 81. This means that h = 9.
The height is 9 inches.
Step-by-step explanation:
mark me as brainliest pls :)
~Alex
Answer:
80%/100%×$24
Step-by-step explanation:
I don't see any options here so let's work it out.
If all prices are reduced by 20%,it implies that 80% of the original value is charged to the buyer as sales price.
Since original value of the pants is $24-100%
then sales value(80%)=(80%/100%×$24)
