The easiest way for me to do this is too set their heights to actual numbers. Say Wanda is 100 feet tall (which I know isn’t a thing, but 100 is always an easy number for percentages.) If will is 34% taller than 100 feet, 1% is 1 foot, so Will is 134 feet tall. 134 / 100 is 134%, so will’s height is 134% of Wanda/s height. Hope this helps!
Answer:
(E) The bias will decrease and the variance will decrease.
Step-by-step explanation:
Given that researchers working the mean weight of a random sample of 800 carry-on bags to e the airline.
We have to find out the effect of increasing the sample size on variance and bias.
We know as per central limit theorem, sample mean follows a normal distribution with mean = sample mean
and std deviation of sample mean = std error = 
Thus std error the square root of variance is inversely proportional to the square root of sample size.
Also whenever we increase sample size the chances of bias would decrease as the sample size becomes larger
So correct answer is both bias and variation will decrease.
(E) The bias will decrease and the variance will decrease.
Answer:
six
Step-by-step explanation:
1,000,000
Answer:
The answer is √10,−√10 (award brainliest)
Step-by-step explanation:
Take the root of both sides and solve.
Exact Form: x = √10,−√10
Decimal Form: x = 3.16227766...,−3.16227766...
for more detailed explanation comment down below this post and ask
57.6² = 33.8² + QR²
QR² = 2.175,32
QR = 46.64
57.6/sen90º = 46.64/sen(P)
sen(P) = 46.64*sen90º/57.6
sen(P) = 0.809
angle P is sen^-1 = 54.06º ≈ 54.1º