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Hunter-Best [27]

3 years ago

7

Provide a possible situation that the graph shown could represent

1 answer:

ANTONII [103]3 years ago

6 0

It depends on what the graph shows. I need to see the graph to help you. sorry

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A sequence is defined recursively by f(1)=16 and f(n)=f(n-1)+2n. Find f(4) 1) 32 2) 30 3) 28 4) 34

ella [17]

$f(1)=16 \ \ \ and \ \ \ \ f(n)=f(n-1)+2n \\ \\f(2)=f(1)+2\cdot2=16+4=20\\ \\f(3)=f(2)+2\cdot3=20+6=26\\ \\f(4)=f(3)+2\cdot4 =26+8=34$

$Ans.\ 4)$

5 0

3 years ago

In help with my Math homework please :) First and correct gets brain.lyest.

andreev551 [17]

See each side
-6/3=-2
other side
3/-6=-1/2
-2=-1/2
false, not equal

-8*9=-72
9*-8=-72
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4 0

3 years ago

Read 2 more answers

Find all solutions to x³+3x² − 9x − 27 = 0 by factoring the equation.

SCORPION-xisa [38]

Answer:

The solutions are $x=-3,\:x=3$

Step-by-step explanation:

To factor this cubic polynomial $x^3+3x^2-9x-27$ you must:

Group the polynomial into two sections

$x^3+3x^2-9x-27=\left(x^3+3x^2\right)+\left(-9x-27\right)$

Factor out -9 from $(-9x-27)$

$(-9x-27)=-9\left(x+3\right)$

Factor out $x^2$ from $(x^3+3x^2)$

$(x^3+3x^2)=x^2\left(x+3\right)$

$x^3+3x^2-9x-27=-9\left(x+3\right)+x^2\left(x+3\right)$

Factor out common term $x+3$

$-9\left(x+3\right)+x^2\left(x+3\right)=\left(x+3\right)\left(x^2-9\right)$

$x^3+3x^2-9x-27=\left(x+3\right)\left(x^2-9\right)$

Factor $x^2-9$

$x^2-9=\left(x+3\right)\left(x-3\right)$

$x^3+3x^2-9x-27= \left(x+3\right)\left(x+3\right)\left(x-3\right)$

$x^3+3x^2-9x-27=\left(x+3\right)^2\left(x-3\right)=0$

Using the Zero Factor Theorem: = 0 if and only if = 0 or = 0

$x+3=0, \quad{x=-3}\\x-3=0, \quad{x=3}$

The solutions are

$x=-3,\:x=3$

3 0

3 years ago

Rapunzel makes $5.78 per hour. Gretta makes $15.46 per hour. How

Alekssandra [29.7K]

Answer:

$9.68 more an hour

Step-by-step explanation:

4 0

3 years ago

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URGENT, HERES THE EQUATION!:)

aev [14]

The answer to the question would be 3.5

4 0

3 years ago