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3 years ago

Put these numbers in order from greatest to least. 9, 9/10, -18/36, 28/40 Please help me

Mathematics

1 answer:

mojhsa [17]3 years ago

4 0

Answer:

9>0.9>0.7>-18/36

Step-by-step explanation:

the smallest would be -18/36.

now we have 9,9/10,28/40

simplify 9/10: 0.9

simplify 28/40: divide 28 and 40 by 4. you will have 7/10 which is equal to 0.7.

now the greatest number is 9,then 0.9 and then 0.7

if anything is unclear, ask freely.

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Ganezh [65]

Answer:

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Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence interval $1-\alpha$ , we have the following confidence interval of proportions.

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In which

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For this problem, we have that:

8 out of the 20 teams in the sample had a season winning percentage better than 0.500. This means that $n = 20, \pi = \frac{8}{20} = 0.4$ .

95% confidence interval

So $\alpha = 0.05$ , z is the value of Z that has a pvalue of $1 - \frac{0.05}{2} = 0.975$ , so $Z = 1.96$ .

The lower limit of this interval is:

$\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.4 - 1.96\sqrt{\frac{0.6*0.4}{20}} = 0.1853$

The upper limit of this interval is:

$\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.4 + 1.96\sqrt{\frac{0.6*0.4}{20}} = 0.6147$

The 95% confidence interval for the true proportion of all teams that had a season winning percentage better than 0.500 is (0.1853, 0.6147).

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