Question

Complete the square to determine the minimum or maximum value of the function defined by the expression.

Answer 1

Answer:

Option D. minimum value at −38

Step-by-step explanation:

we have

$x^{2}-12x-2$

Let

$y=x^{2}-12x-2$

Complete the square

$y+2=x^{2}-12x$

$y+2+36=(x^{2}-12x+36)$

$y+38=(x^{2}-12x+36)$

$y+38=(x-6)^{2}$

$y=(x-6)^{2}-38$ ------> equation of a vertical parabola in vertex form

The vertex is the point $(6,-38)$

The parabola open upward-----> the vertex is a minimum

therefore

minimum value at −38