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Zarrin [17]
3 years ago
13

Complete the square to determine the minimum or maximum value of the function defined by the expression.

Mathematics
1 answer:
FrozenT [24]3 years ago
3 0

Answer:

Option D. minimum value at −38

Step-by-step explanation:

we have

x^{2}-12x-2

Let

y=x^{2}-12x-2

Complete the square

y+2=x^{2}-12x

y+2+36=(x^{2}-12x+36)

y+38=(x^{2}-12x+36)

y+38=(x-6)^{2}

y=(x-6)^{2}-38 ------> equation of a vertical parabola in vertex form

The vertex is the point (6,-38)

The parabola open upward-----> the vertex is a minimum

therefore

minimum value at −38

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