Comentario personal de Pedro Páramo capítulo 23 a 45

Spanish

1 answer:

iVinArrow [24]3 years ago

4 0

Answer:Personal comment of Pedro Páramo chapter 23 to 45

Explanation:

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$We \ first, \ simplify \ \frac{125}{2} \\ \\ \left[\begin{array}{ccc}((x^3)-( \frac{125}{2}*x))-10 \end{array}\right] \\ \\ \boxed{\boxed{x^3= \frac{x^3}{1} = \frac{x^3*2}{2} }} \\ \\ \\ \boxed{ \frac{x^3*2-(125x)}{2} = \frac{2x^3-125x}{2} } \\ \\ \\ \frac{(2^3-125x}{2} -10 \\ \\ pulling \ out \ like \ factors : \\ \\ 2x^3 - 125x = x * (2x^2 - 125) \\ \\ Factoring: \ 2x^2 - 125$

Here's how!

$Proof : \ (A+B) * (A-B) =\\
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 A2 - B2\\$

Therefore . . .

$\boxed{ \frac{x*(2x^2-125)-(10*2)}{2} = \frac{2x^3-125x-20}{2} }$

The factors would then be the following:

→ $( Leading \ Coefficient : 1,2)$
→ $(Trailing Constant) : 1 ,2 ,4 ,5 ,10 ,20$

By then, understanding on how we have got in our terms, such as the like terms, and also how we have understanded the coefficient's, we would then have our answer clear below.

$\leadsto \ Your \ answer: \boxed{\bf{ \frac{2x^3-125x-20}{2} }}$ ✔

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