Question isn't well formatted :
If I have 48 cards and and gave 10 to my friend and I have 38 left. what fraction of original number of card do I have left.
Answer:
0.7917
Step-by-step explanation:
If I have 48 cards and and gave 10 to my friend and I have 38 left what what fractionbb be is my original number of cards
Given that :
Total number of cards = 48
Number given to friend = 10
Number of cards left = 48 - 10 = 38
Number of cards left / original number of cards
38 / 48
= 0.7917
They had the same quotient because both of those equations are equal
Answer:
Step-by-step explanation:
If a polynomial intersects the x-axis at (2,0) and (-2,0)
Then the zeroes are at x=2 and x=-2
(Outside of the question)
To find factors using the zeroes, we must have one side of the equation equal to zero.
x=2
x-2=0
factor (x-2)
x=-2
x+2=0
factor (x+2)
Answer:
Step-by-step explanation:
CH4
carbon and hydrogen (4)
O2
oxygen (2)
CO2
carbon and oxygen
2H20
hydrogen and oxygen (water) (2)
<span>
6 Find an exact value. sin 75°
</span>sin(A+B)=sin(A)cos(B)+cos(A)sin<span>(B)
</span>sin(45)=cos(45)=(2^0.5)/2 sin(30)=0.5 cos(30)=(3^0.5)/2
sin(45+30)=sin(45)cos(30)+cos(45)sin(30)=(6^0.5+2^0.5)/4
the answer is the letter d) quantity square root of six plus square root of two divided by four.
<span>
7. Find an exact value. sine of negative eleven pi divided by twelve.
</span>sin(-11pi/12) = -sin(11pi/12) = -sin(pi - pi/12) = -sin(pi/12) = -sin( (pi/6) / 2)
= - sqrt( (1-cos(pi/6) ) / 2) = -sqrt( (1-√3/2) / 2 ) = -(√3-1) / 2√2=(√2-√6)/4
the answer is the letter c) quantity square root of two minus square root of six divided by four.
<span>
8. Write the expression as the sine, cosine, or tangent of an angle. sin 9x cos x - cos 9x sin x
</span>
sin(A−B)=sinAcosB−cosAsinB
sin(9x−x)= sin9xcosx−cos9xsinx= sin(8x)
the answer is the letter c) sin 8x
<span>
9. Write the expression as the sine, cosine, or tangent of an angle. cos 112° cos 45° + sin 112° sin 45°</span>
cos(A−B)=cosAcosB<span>+sinA</span>sinB
cos(112−45)=cos112cos45<span>+sin112</span>sin45=cos(67)
the answer is the letter d) cos 67°
10. Rewrite with only sin x and cos x.
sin 2x - cos 2x
sin2x =
2sinxcosx<span>
cos2x = (cosx)^2 - (sinx)^2 = 2(cosx)^2 -1 = 1- 2(sinx)^2</span>
sin2x- cos2x=2sinxcosx-(1- 2(sinx)^2=2sinxcosx-1+2(sinx)^2
sin2x- cos2x=2sinxcosx-1+2(sinx)^2
<span>
the answer is the letter <span>
b) 2 sin x cos2x - 1
+ 2 sin2x</span></span>
