Answer:
show us
Step-by-step explanation:
Let Ch and C denote the events of a student receiving an A in <u>ch</u>emistry or <u>c</u>alculus, respectively. We're given that
P(Ch) = 88/520
P(C) = 76/520
P(Ch and C) = 31/520
and we want to find P(Ch or C).
Using the inclusion/exclusion principle, we have
P(Ch or C) = P(Ch) + P(C) - P(Ch and C)
P(Ch or C) = 88/520 + 76/520 - 31/520
P(Ch or C) = 133/520
2/32 - 1/16 this is the probability (in fractions)
Answer:
2(2/5x+2)=4x/5+4
Step-by-step explanation:
2(2/5x+2)=4x/5+4
4x/5 +4=4x/5 +4