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timurjin [86]
3 years ago
12

Aqueous strontium sulfide and aqueous copper(II) sulfate

Chemistry
1 answer:
ryzh [129]3 years ago
5 0

Answer: The reaction does occur.

Explanation: For the reaction of aqueous strontium sulfide and aqueous copper(II) sulfate, the reaction follows:

SrS(aq.)+CuSO_4(aq.)\rightarrow SrSO_4(aq.)+CuS(s)

This reaction is a type of precipitation reaction.

The precipitate formed is CuS which is black in color.

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Elements are identified by the number of
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6 0
4 years ago
Identify the terms,like terms,coefficients and constants <br><br><br> 2+3a+9a
yawa3891 [41]
Like terms in algebra are terms that have the same variables and power. Constants contain only numbers, we call them constants because their values don't change. Coefficients are the numbers in front of the variable ex: 5y in that expression 5 is the coefficient. So in the expression 2+3a+9a there is one constant which is 2 the likes terms are 3a and 9a because they have the same variable. And the coefficients are 3 and 9 because they are in front of the variable.
7 0
3 years ago
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Choose the element that is more reactive: oxygen or argon.
Mazyrski [523]
I choose oxygen because
7 0
4 years ago
What is the name of S2Br6
Nikitich [7]

Answer:

disulfur hexabromide

Explanation:

First, <u>identify the element names </u>using your periodic table.

"S" means sulfur. "Br" means bromine. The <u>second element drops the ending and adds "-ide"</u>.

S₂Br₆

sulfur bromide

Decide if the compound is <u>ionic or covalent</u>.

Since there are two non-metals, this is a covalent compound. So, will use Greek prefixes for the number of atoms. You can see the list below and find "2" and "6".

S₂Br₆

disulfur hexabromide

List of Greek number prefixes:

1 mono

2 di

3 tri

4 tetra

5 penta

6 hexa

7 hepta

8 octa

9 nona

10 deca

The name of S₂Br₆ is disulfur hexabromide.

6 0
3 years ago
Consider the reaction
Fofino [41]
a) According to the reaction equation:

CaSO4(s) ↔ Ca2+(aq)  + SO4-(aq)

when Kc = [Ca2+][SO4-]

when [Ca2+] = [SO4-] = X

and we have Kc = 2.4 x 10^-5 so ,by substitution we can get [Ca2+]&[SO4-] 

2.4 x 10^-5 = X^2

∴X = 0.0049

∴[SO4-] = [Ca2+] = 0.0049 M

b) when we have [Ca2+] =  0.0049 M so we can get the no.of moles of CaSO4:

moles of CaSO4 = molarity * volume 

                             = 0.0049 M * 1.2 L
                             = 0.00588 moles

when we know the molar mass of CaSO4 = 136.14 g/ mol, So we can get the mass:

∴mass of CaSO4 = moles of CaSO4 * molar mass of CaSO4

                             = 0.00588 moles * 136.14 g/mol

                             = 0.8 g
8 0
3 years ago
Read 2 more answers
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