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cluponka [151]
3 years ago
13

Plz answer ill give brainliest i only need 3 if you answer all your a living legend

Mathematics
1 answer:
Marat540 [252]3 years ago
6 0

Answer:

it is ∠5

Step-by-step explanation:

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Please help with this Ive been stressing out lately and I want a break I'll give hearts and 5 stars.
Anit [1.1K]

Answer:

8.8584073464

Step-by-step explanation:

area of the rectangle is 12

area of the circle is just pie

subtract the two and you get 8.8584073464

8 0
3 years ago
Read 2 more answers
When hourly employees work beyond 40 hours in a week, federal law requires that they receive __________ pay. A. commissioned B.
Zolol [24]

Answer: D

Step-by-step explanation:

3 0
2 years ago
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Suppose twenty-two communities have an average of = 123.6 reported cases of larceny per year. assume that σ is known to be 36.8
Delvig [45]
We are given the following data:

Average = m = 123.6
Population standard deviation = σ= psd = 36.8
Sample Size = n = 22

We are to find the confidence intervals for 90%, 95% and 98% confidence level.

Since the population standard deviation is known, and sample size is not too small, we can use standard normal distribution to find the confidence intervals.

Part 1) 90% Confidence Interval
z value for 90% confidence interval = 1.645

Lower end of confidence interval = m-z *\frac{psd}{ \sqrt{n} }
Using the values, we get:
Lower end of confidence interval=123.6-1.645* \frac{36.8}{ \sqrt{22}}=110.69

Upper end of confidence interval = m+z *\frac{psd}{ \sqrt{n} }
Using the values, we get:
Upper end of confidence interval=123.6+1.645* \frac{36.8}{ \sqrt{22}}=136.51

Thus the 90% confidence interval will be (110.69, 136.51)

Part 2) 95% Confidence Interval
z value for 95% confidence interval = 1.96

Lower end of confidence interval = m-z *\frac{psd}{ \sqrt{n} }
Using the values, we get:
Lower end of confidence interval=123.6-1.96* \frac{36.8}{ \sqrt{22}}=108.22

Upper end of confidence interval = m+z *\frac{psd}{ \sqrt{n} }
Using the values, we get:
Upper end of confidence interval=123.6+1.96* \frac{36.8}{ \sqrt{22}}=138.98

Thus the 95% confidence interval will be (108.22, 138.98)

Part 3) 98% Confidence Interval
z value for 98% confidence interval = 2.327

Lower end of confidence interval = m-z *\frac{psd}{ \sqrt{n} }
Using the values, we get:
Lower end of confidence interval=123.6-2.327* \frac{36.8}{ \sqrt{22}}=105.34
Upper end of confidence interval = m+z *\frac{psd}{ \sqrt{n} }
Using the values, we get:
Upper end of confidence interval=123.6+2.327* \frac{36.8}{ \sqrt{22}}=141.86

Thus the 98% confidence interval will be (105.34, 141.86)


Part 4) Comparison of Confidence Intervals
The 90% confidence interval is: (110.69, 136.51)
The 95% confidence interval is: (108.22, 138.98)
The 98% confidence interval is: (105.34, 141.86)

As the level of confidence is increasing, the width of confidence interval is also increasing. So we can conclude that increasing the confidence level increases the width of confidence intervals.
3 0
3 years ago
What is the median of this data set
MatroZZZ [7]

Answer:

52.5

Step-by-step explanation:

median is where u find the middle number

put them in order first

24,28,51,54,67,70

its between 54 and 51

3 0
2 years ago
If ||| m, solve for x and y.
rosijanka [135]

Answer:

x = 11, y = 3

Step-by-step explanation:

(13x - 19) and (9x + 25) are corresponding angles and congruent, thus

13x - 19 = 9x + 25 ( subtract 9x from both sides )

4x - 19 = 25 ( add 19 to both sides )

4x = 44 ( divide both sides by 4 )

x = 11

Then

13x - 19 = 13(11) - 19 = 143 - 19 = 124

(17y + 5) and 124 are alternate angles and are supplementary, thus

17y + 5 + 124 = 180, that is

17y + 129 = 180 ( subtract 129 from both sides )

17y = 51 ( divide both sides by 17 )

y = 3

4 0
2 years ago
Read 2 more answers
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