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mihalych1998 [28]

4 years ago

7

a normal distribution has a mean of 10 and a standard deviation of 1 what is the probability of selecting a number between 8 and

11

1 answer:

rusak2 [61]4 years ago

5 0

Answer:

0.815

Step-by-step explanation:

First, find the z-scores.

z = (x − μ) / σ

z₁ = (8 − 10) / 1

z₁ = -2

z₂ = (11 − 10) / 1

z₂ = 1

P(-2 < Z < 1) = P(Z < 1) − P(Z < -2)

Use a chart, calculator, or the empirical rule to find the probability.

Using the empirical rule:

P(-2 < Z < 1) = 0.84 − 0.025

P(-2 < Z < 1) = 0.815

Using a chart:

P(-2 < Z < 1) = 0.8413 − 0.0228

P(-2 < Z < 1) = 0.8185

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Ralph Chase plans to sell a piece of property for $160,000. He wants the money to be paid off in two ways monica short-term no

DerKrebs [107]

Answer:

short-term: $90,000
long-term: $70,000

Step-by-step explanation:

Let x represent the amount borrowed on the short term. Then 160000-x is the amount of the long-term note. The total interest is ...

0.11x +0.08(160000-x) = 15500

0.03x + 12800 = 15500 . . . . simplify

0.03x = 2700 . . . . . . . . . subtract 12800

x = 2700/.03 = 90,000 . . . . short-term note

160,000 -90,000 = 70,000 . . . . long-term note

The short-term note was for $90,000; the long-term note was for $70,000.

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3 years ago

What is the solution to the equation?<br> 5 = 2 a<br> /5

Nimfa-mama [501]

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5 0

4 years ago

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An 8.0 kg block is moving at 3.2 m/s. A net force of 10 N is constantly applied on the block in the direction of its movement, u

Softa [21]

Answer:

5.02 m/s

Step-by-step explanation:

We are given that

Mass of block,m=8 kg

Initial velocity,u=3.2 m/s

Net force ,F=10 N

Distance,s=6 m

We have to find the approximate final velocity of the block.

We know that $a=\frac{F}{m}$

Using the formula

$a=\frac{10}{8}=\frac{5}{4} m/s^2$

We know that

$v=\sqrt{u^2+2as}$

Using the formula

$v=\sqrt{(3.2)^2+2\times \frac{5}{4}\times 6}$

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3 years ago

PLZ HURRY IT'S URGENT!!

FromTheMoon [43]

Option C: $\frac{4}{5}$ is the slope of the line

Explanation:

The line passes through the points $(3,-1)$ and $(-2,-5)$

We need to find the slope of the line.

The slope can be determined using the formula,

$m=\frac{y_2-y_1}{x_2-x_1}$

Where the coordinates $(x_1,y_1)$ and $(x_2,y_2)$ are $(3,-1)$ and $(-2,-5)$

Let us substitute the points in the formula

Thus, we have,

$m=\frac{-5-(-1)}{-2-3}$

Simplifying, we get,

$m=\frac{-5+1}{-2-3}$

Adding the numerator and denominator, we have,

$m=\frac{-4}{-5}$

Cancelling the negative terms, we get,

$m=\frac{4}{5}$

Thus, the slope of the line is $m=\frac{4}{5}$

Therefore, Option C is the correct answer.

5 0

3 years ago

Plz help, I'm taking an Advanced class (Algebra) Will give brainliest ✔✔✔✔✔✔✔✔✔

bija089 [108]

Part A:

The average rate of change refers to a function's slope. Thus, we are going to need to use the slope formula, which is:

$m = \dfrac{y_2 - y_1}{x_2 - x_1}$

$(x_1, y_1)$ and $(x_2, y_2)$ are points on the function

You can see that we are given the x-values for our interval, but we are not given the y-values, which means that we will need to find them ourselves. Remember that the y-values of functions refers to the outputs of the function, so to find the y-values simply use your given x-value in the function and observe the result:

$h(0) = 3(5)^0 = 3 \cdot 1 = 3$

$h(1) = 3(5)^1 = 3 \cdot 5 = 15$

$h(2) = 3(5)^2 = 3 \cdot 25 = 75$

$h(3) = 3(5)^3 = 3 \cdot 125 = 375$

Now, let's find the slopes for each of the sections of the function:

<u>Section A</u>

$m = \dfrac{15 - 3}{1 - 0} = \boxed{12}$

<u>Section B</u>

$m = \dfrac{375 - 75}{3 - 2} = \boxed{300}$

Part B:

In this case, we can find how many times greater the rate of change in Section B is by dividing the slopes together.

$\dfrac{m_B}{m_A} = \dfrac{300}{12} = 25$

It is 25 times greater. This is because $3(5)^x$ is an exponential growth function, which grows faster and faster as the x-values get higher and higher. This is unlike a linear function which grows or declines at a constant rate.

7 0

4 years ago