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Alex_Xolod [135]
3 years ago
11

What is the approximate distance around the half circle with a diameter of 64 meters?

Mathematics
1 answer:
nikdorinn [45]3 years ago
6 0
Its A 100.48 
64*3.14=200.96
200.96/2=100.48 
easy

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Lee el texto y sustituye las palabras resaltadas por frases adverbiales que expresen temporalidad​
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3 years ago
Please help, this is my review, and I have a test tomorrow. But based on what I did, none of my answers matched the ones below.
lukranit [14]

Answer:

  a)  21, 34.5, 54.75, 85.125

Step-by-step explanation:

All of the answer choices differ in the first term, so that is the only one you need to figure here. However, we will do them all, so you can see it done.

We note that x > 0 for all of the values of x that we need to use. That means the recursive relation is the one we're using for computation.

f(1) = 3/2·f(0) +3 = (3/2)(12) + 3 = 18 +3 = 21 . . . . . . matches choice (a)

f(2) = 3/2·f(1) +3 = (3/2)(21) +3 = 63/2 +3 = 69/2 = 34.5

f(3) = 3/2·f(2) +3 = (3/2)(34.5) +3 = 51.75 +3 = 54.75

f(4) = 3/2·f(3) +3 = (3/2)(54.75) +3 = 82.125 +3 = 85.125

__

When you're computing for sequential input values, each depends on the previous value you computed.

_____

<em>Additional comment</em>

Using an exponential regression calculator (or spreadsheet), the explicit function can be found to be ...

  f(x) = 18·1.5^x -6

6 0
2 years ago
Multiple choice! Pls help :) i really need help!
Solnce55 [7]

Answer:

A and D

Step-by-step explanation:

7 0
3 years ago
13) If AOBC is a rectangle whose three vertices are A(0,3), (0,0) and B(5,0).
Levart [38]

Answer:

(b) 68

Step-by-step explanation:

Distance between two points:

Suppose that we have two points, (x_1,y_1) and (x_2,y_2). The distance between them is given by:

D = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

Diagonal:

Diagonals are a line between opposite points in a square.

In this question, it is between A(0,3) and B(5,0), and between (0,0) and (5,3). Both these diagonals have the same measure, and are the distance between these points. So

D = \sqrt{(5-0)^2+(3-0)^2} = \sqrt{5^2 + 3^2} = \sqrt{34}

Then sum of the squares of its both diagonals is units

Both diagonals measure \sqrt{34}. Sum of squares is:

(\sqrt{34})^2 + (\sqrt{34})^2 = 34 + 34 = 68

The correct answer is given by option b.

6 0
3 years ago
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