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Oksi-84 [34.3K]
3 years ago
5

Does anyone get this!??

Mathematics
1 answer:
stepladder [879]3 years ago
8 0

Hello from MrBillDoesMath!

Answer:

8

Discussion:

Let the number be "n". Then the question states that

3n - 15 = (n/2) + 5             => multiply both sides by 2

6n - 30 = n + 10                => subtract n from both sides

5n - 30 = 10                      => add 30 to both sides

5n = 30 + 10 = 40            => divide both sides by 5

n = 40/5 = 8

Thank you,

MrB

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A(t)=250-230e^{-\frac{t}{50} }

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\frac{dA}{dt}+\frac{A(t)}{50} = 5\\\\The\ integrating\ factor(IF)= e^{\int\limits \frac{1}{50}dt }=e^{\frac{t}{50} }\\\\Multiplying\ through\ by\ the\ I.F:\\\\\frac{dA}{dt}*e^{\frac{t}{50} }+\frac{A(t)}{50}*e^{\frac{t}{50} } = 5*e^{\frac{t}{50} }\\\\Integrating \ both \ sides:\\\\\int\limits[  \frac{dA}{dt}*e^{\frac{t}{50} }+\frac{A(t)}{50}*e^{\frac{t}{50} }] dt=\int\limits  5e^{\frac{t}{50} } dt\\\\A(t)e^{\frac{t}{50} } =\int\limits  5e^{\frac{t}{50} } dt\\\\

A(t)e^{\frac{t}{50} } =250e^{\frac{t}{50} }+C\\\\A(t)=250+Ce^{-\frac{t}{50} }\\\\But\ A(0) = 20\\\\20=250+Ce^{-\frac{0}{50} }\\\\C+250=20\\\\C=-230\\\\A(t)=250-230e^{-\frac{t}{50} }

7 0
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Answer:

Domain : { x| x≥3}

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The domain is the input values ( the x values)

X starts at 3 and goes to infinity

Domain : { x| x≥3}

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