Answer: 
Step-by-step explanation:
We can use the Rational Root Test.
Given a polynomial in the form:
Where:
- The coefficients are integers.
- 
is the leading coeffcient (
)
- 
is the constant term 
Every rational root of the polynomial is in the form:
For the case of the given polynomial:
We can observe that:
- Its constant term is 6, with factors 1, 2 and 3.
- Its leading coefficient is 2, with factors 1 and 2.
Then, by Rational Roots Test we get the possible rational roots of this polynomial:
Step-by-step explanation:
This means that if a line is perpendicular to a line that has slope m, then the slope of the line is -1 / m. For example, we found that the slope of the line y = (1/2)x + 3 is 1/2. Thus any line that is perpendicular to this line would have slope -2 /1 = -2.
Let's start with our parent function:
f(x) = sin x
One cycle on this graph occurs between 0 and 2π. Therefore, our b-value is one.
There is no vertical shift up. The sinusoidal axis is along y = 0.
The wave is not inverted, it starts at the origin and rises on both the y and x axis. Thus there is no negative value before the function.
The amplitude of the wave is 3. A normal sine wave rises to a maximum of 1, but this is multiplied by 3.
f(x) = 3 sin x
There are an infinite amount of equations that could be used to represent this graph, but this is perhaps the most intuitive.
I saw the images that accompanied this problem.
2 circles: circle 1 has 6 slices ; circle 2 has 3 slices
Circle 1 is for Tom: you can shade 4 slices out of the 6 slices.
Circle 2 is for Liz: you can shade 2 slices out of the 3 slices.
4/6 is equal to 2/3 because when 4 and 6 are both divided by 2, they give quotient of 2 and 3, respectively.
4 ÷ 2 = 2
6 ÷ 2 = 3
T(2)=d you multiply <em>t</em> times 2 to get <em>d</em>
