<h3>
Answer: k^2*p^6</h3>
Work Shown:
s = length of each side
s = kp^3
A = area of square
A = s^2
A = s*s
A = (kp^3)*(kp^3)
A = (k*k)*(p^3*p^3)
A = k^2*p^6
To multiply the terms, you add the exponents. Think of k as k^1, so k*k = k^1*k^1 = k^(1+1) = k^2
I believe it is b, but only if the two angles are in place already.
Answer:
x=-15/14
Step-by-step explanation:
1/3x+5/6x=-2+3/4
7/6x=-5/4
x=-15/14
Answer: The required matrix is
![A=\left[\begin{array}{ccc}6&4&0\\0&6&8\\0&0&6\end{array}\right] .](https://tex.z-dn.net/?f=A%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D6%264%260%5C%5C0%266%268%5C%5C0%260%266%5Cend%7Barray%7D%5Cright%5D%20.)
Step-by-step explanation: The given linear transformation is
T(f(t)) = 4f'(t) + 6f(t).
We are to find the matrix A of T from P² to P² with respect to the standard basis P² = {1, t, t²}.
We have

Therefore, the matrix A is given by
![A=\left[\begin{array}{ccc}6&4&0\\0&6&8\\0&0&6\end{array}\right] .](https://tex.z-dn.net/?f=A%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D6%264%260%5C%5C0%266%268%5C%5C0%260%266%5Cend%7Barray%7D%5Cright%5D%20.)
Thus, the required matrix is
![A=\left[\begin{array}{ccc}6&4&0\\0&6&8\\0&0&6\end{array}\right] .](https://tex.z-dn.net/?f=A%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D6%264%260%5C%5C0%266%268%5C%5C0%260%266%5Cend%7Barray%7D%5Cright%5D%20.)
Answer:
The value of x = 2
Step-by-step explanation:
Given algebraic expression as :

Or, 10x + 6 = 4x + 18
Or, 10x - 4x = 18 - 6
Or, 6x = 12
Or, x = 
∴ x = 2
Hence The value of x is 2 Answer