Answer:
1: 31.5. 2: 5. 3: 4.6 4: 45
Answer:
Number of fish in 2006 = 845 fishes (Approx.)
Step-by-step explanation:
Given;
Number of fish in 2000 = 1,150 fishes
Decreasing rate = 5% per year
Find:
Number of fish in 2006
Computation:
Exponential decay function:
F = P[1-r]ⁿ
Number of year = 2006 - 2000
Number of year = 6 year
Number of fish in 2006 = 1,150[1-5%]⁶
Number of fish in 2006 = 1,150[1-0.05]⁶
Number of fish in 2006 = 1,150[0.95]⁶
Number of fish in 2006 = 1,150[0.735]
Number of fish in 2006 = 845.25
Number of fish in 2006 = 845 fishes (Approx.)
Answer: The required probability is 
Step-by-step explanation:
Since we have given that
Number of spruce tree = 20
Number of maple tree = 50
Total trees = 70
We need to find the experimental probability that the next tree Colleen to get a spruce tree.
So, the probability would be :
Hence, the required probability is
Answer:
3^2
Step-by-step explanation:
=3^3+3/3^4
=3^6/3^4
=3^6-4
=<u>3^2</u>
Formula we use,
→ P = 2(L + W)
Then the value of L and W is,
→ P = 2(L + W)
→ 48 = 2(2x + x)
→ 2(3x) = 48
→ x = 48/6
→ [ x = 8 ]
Then the width will be,
→ W = x = 8 ft
Hence, the width is 8 ft.
Now the length will be,
→ L = 2x = 2(8) = 16 ft
Therefore, the length is 16 ft.
