Please help precalculus
1 answer:
The max value can be found by setting the derivative equal to 0 and solving for x, then subbing that value for x back into the original function and solving for y. 
which simplifies to 
. This derivative is equal to 0 when -4x is equal to 0. If -4x = 0, then x = 0. If we find f(0), then 
and y here is 2/3. So the max value occurs at (0, 2/3). There you go!
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Answer: The answers is alternate interior angles.
Step-by-step explanation: First of all, the questions marks given in the figure are renamed in the attached figure as (a), (b), (c) and (d).
For (a): Since AC is parallel to A'C' and A'D is a transversal for these two parallel lines, so, ∠CDB' = ∠B'A'C', because these are alternate interior angles.
For (b): Since BC is parallel to B'C' and A'B' is a transversal, so ∠BEB' = ∠A'B'C', because these are alternate interior angles.
For (c): Since AB is parallel to A'B' and AD is a transversal, so ∠BAC = ∠CDB', because these are alternate interior angles.
For (d): Since AB is parallel to A'B' and BE is a transversal, so ∠ABC = ∠BEB', because these are alternate interior angles.
Thus, all the questions marks are the reasons that the given angles are equal because they are alternate interior angles.
