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Lerok [7]
3 years ago
8

Please help precalculus

Mathematics
1 answer:
aleksley [76]3 years ago
3 0
The max value can be found by setting the derivative equal to 0 and solving for x, then subbing that value for x back into the original function and solving for y.  f'(x)= \frac{(x^2+3)(0)-2(2x)}{(x^2+3)^2} which simplifies to f'(x)= \frac{-4x}{(x^2+3)^2}.  This derivative is equal to 0 when -4x is equal to 0.  If -4x = 0, then x = 0.  If we find f(0), then f(0)= \frac{2}{(0)^2+3} and y here is 2/3.  So the max value occurs at (0, 2/3).  There you go!
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Help me please im trying to do this but dont understand it at all.
Umnica [9.8K]

The attached graph represents the graph of the function g(x)

<h3>How to determine the function g(x)?</h3>

The function f(x) is an absolute value function.

An absolute value function is represented as:

y = a|x - h| + k

Where

Vertex = (h, k)

From the graph, we have:

(h, k) = (-3, -2)

So, we have:

y = a|x + 3| - 2

Also, we have:

(x, y) = (-1, 0)

So, we have:

0 = a|-1 + 3| - 2

This gives

0 = 2a - 2

Solve for a

a = 1

Substitute a = 1 in y = a|x + 3| - 2

y = |x + 3| - 2

This means that

f(x) = |x + 3| - 2

We have:

g(x) = 2f(x)

This means that:

g(x) = 2(|x + 3| - 2)

So, we have:

g(x) = 2|x + 3| - 4

See attachment for the graph of g(x)

Read more about absolute value functions at:

brainly.com/question/10664936

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5 0
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When Joseph first starts working at a grocery store, his hourly rate is $10. For each year he works at the grocery store, his ho
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Answer: R(t) = 10 + 0.50t

Step-by-step explanation:

From the question, we've been informed that Joseph's hourly rate is $10 and that for every year he works at the grocery store, his hourly rate increases by $0.50.

Therefore, the function will be

R(t) = 10 + 0.50t

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3 years ago
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Answer:

It's A. (2, 0) and (0, -4)

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Is (10,8) a solution of y =1/2x+3
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Answer:

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Step-by-step explanation:

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